The required probability is 4/25.
We want to realize the concept of chance to remedy this question.
First we will find the chance that the system on which I play is a wheel of fortune system.
So, required probability quantity of wheel of fortune machines ÷ total range of machines
= 8/10
= 4/5
Now the probability of wheel of fortune winning is 20%.
So, total probability that if I play and win and that machine is a wheel of fortune machine is= (4/5)×(20/100)
= (4/5)×(1/5)
= 4/25
Hence, the required probability is 4/25.
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Answer:
Step-by-step explanation:
7) R(3 , -9) ; S ( -4,5) ,T (-8,13)
RS = √(x₂ - x₁)² + (y₂ - y₁)²
= √(-4 -3)² + ( 5 - [-9] )² = √(-4 -3)² + ( 5 + 9 )²
= √(-7)² + ( 14)² =√ 49 + 196= √ 245
ST = √( -8 - [-4] )²+ (13 - 5)² + = √(-8 + 4)² + ( 13 - 5 )²
= √(-4)² + ( 8)² =√ 16 + 64= √ 80
RS ≠ ST
8) S is not the midpoint of RT.
9) AB = 14
AB + BC = AC
14 + 3X - 4 = 4X + 4
4X - 3X = 14 - 4 - 4
X = 6
AC = 4x + 4 = 4*6 + 4 = 24 + 4 = 28
BC = 3x - 4 = 3*6 - 4 = 18 -4 = 14
10)AB = BC .So B is the midpoint of AC
3√6 - 4√6
3(2.45) - 4(2.45)
[not sure how your teacher wants you to round the square root of six but here is mine.]
7.35 - 9.8
-2.45
On this question, we can use the order of operations. ( pemdas )
First, we must fill in the missing numbers.
9*21 + (3*3)21 + 12
Start in the parentheses.
(3*3)21 = 9*21 = 189
189+189+12
The rest is just addition now!
189+189+12=390
390 is the correct answer.