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Ivenika [448]
3 years ago
8

Please help meee! I will give brainleiest!

Mathematics
1 answer:
Serjik [45]3 years ago
5 0

Answer:

B) 3.0 ml

Step-by-step explanation:

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A circle is represented by the equation x2+y2=445. a) State the radius. b) Find y if point A(-9,y) is on this circle.
Temka [501]

Answer:

R= sqrt 445

Y = 19

Step-by-step explanation:

Radius is the square root of 445

Find y

So, First step is to substitute what you have

-9^2 + y^2 = 445

 81 + y^2 = 445

-81               -81

y^2 =364

Y is about 19

Let me know if I'm incorrect

Hope this helps :)

4 0
3 years ago
What is the common ratio for this geometric sequence 3,12,48,192
NARA [144]

Answer: The common ratio is 4.

Step-by-step explanation:

Each term is four times the last term.  The common ratio of a geometric sequence is the number that is being multiplied by each time to get the next term, which is four in this case.

8 0
3 years ago
Helpppppppppppppppppp
schepotkina [342]

Answer: 4b+9

Step-by-step explanation: add the B's together

6 0
3 years ago
Read 2 more answers
Solve.
Ksenya-84 [330]
<span>Solve.

x² + 4x + 4 = 18


​ A x=−4±3√ ​2

​ B x=2±3√ ​2

​ C x=4±9√ ​2

D x=−2±3√2



</span>x^2 + 4x + 4 = 18 \\  \\ x^2+4x+4-18= 0 \\  \\ x^2+4x-14=0 \\  \\ x_1_y_2=  \dfrac{-b\pm \sqrt{b^2-4ac} }{2a} \qquad a= 1\qquad b= 4\qquad c= -14 \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{4^2-4(1)(-14)} }{2(1)} \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{16-(-56)} }{2}  \\  \\  \\  x_1_y_2=  \dfrac{-4\pm \sqrt{72} }{2}  \\  \\  \\  x_1=  \dfrac{-4+ \sqrt{72} }{2} \qquad\qquad x_2=  \dfrac{-4+ \sqrt{72} }{2}\\  \\  \\  x_1=  \dfrac{-4+ \sqrt{2^3*3^2} }{2} \qquad\qquad x_2=  \dfrac{-4- \sqrt{2^3*3^2} }{2}
<span>
</span>x_1=  \dfrac{-4+2*3 \sqrt{2} }{2} \qquad\qquad x_2=  \dfrac{-4- 2*3\sqrt{2} }{2} \\  \\  \\ x_1=  \dfrac{-4+6 \sqrt{2} }{2} \qquad\qquad x_2=  \dfrac{-4- 6\sqrt{2} }{2} \\  \\  \\ x_1=  \dfrac{-4}{2} + \dfrac{6 \sqrt{2} }{2} \qquad\qquad x_2=   \dfrac{-4}{2}- \dfrac{ 6\sqrt{2} }{2} \\  \\  \\  x_1= -2 + 3 \sqrt{2} \qquad\qquad\quad  x_2=  -2- 3\sqrt{2}  \\  \\  \\ \boxed{x=   -2\pm 3\sqrt{2} }  \to D)<span>
</span>
7 0
3 years ago
Read 2 more answers
What is the reason for each step in the solution of the equation?
Alexxx [7]

as you can see you have to use commutative property given !!!!!!!!!


8 0
3 years ago
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