Following the Hardy-Weinberg equilibrium theory, the frequency of the heter0zyg0us genotype is 2pq. In the exposed example, 2pq = 0.48.
<h3>
Hardy-Winberg equilibrium</h3>
The Hardy-Weinberg equilibrium theory states that the allelic frequencies in a locus are represented as p and q.
Assuming a diallelic gene,
→ The allelic frequencies are
- p is the frequency of the dominant allele,
- q is the frequency of the recessive allele.
→ The genotypic frequencies after one generation are
- p² (H0m0zyg0us dominant genotypic frequency),
- 2pq (Heter0zyg0us genotypic frequency),
- q² (H0m0zyg0us recessive genotypic frequency).
If a population is in H-W equilibrium, it gets the same allelic and genotypic frequencies generation after generation.
The addition of the allelic frequencies equals 1 ⇒ p + q = 1.
The sum of genotypic frequencies equals 1 ⇒ p² + 2pq + q² = 1
If the allele A has a frequency of 0.6, and the allele B has a frequency of 0.4, then the frequency of the heter0zyg0us genotype is
2pq = 2 x 0.6 x 0.4 =<u> 0.48</u>
You can learn more about the Hardy-Weinberg equilibrium at
brainly.com/question/3406634
<span>Cells need a source of energy, they get this energy by breaking down food molecules to release, the stored chemical energy.This process is called 'cellular respiration'. The process is happens in all the cells in our body. Oxygen is used to oxidize food, main oxidized food is sugar(glucose).</span><span>Jan 14, 2009</span>
activities of living organisms (animals, burrows, plant roots), pressure from overlying load/materials and atmospheric conditions.
Answer:
Mitosis Occupies a Portion of the Cell Cycle
Explanation:
Today, scientists know that Flemming had successfully distinguished chromosomes in the interphase portion of the cell cycle from chromosomes undergoing mitosis, or the portion of the cell cycle during which the nucleus divides
