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3 years ago

Estimating the products of decimal numbers 46.6 × 37. 2 =

Mathematics

1 answer:

Art [367]3 years ago

8 0

1. 1,734
2. 1,672
3. 2,420
4. 3,902
5. 2,382
These are the correct answer to the products of the decimal numbers

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Graph the systems of equations to find the solution.

frutty [35]

The solution is (8,-9).

7 0

3 years ago

20 points and Brainliest if answered and explained!

Rasek [7]

What you need to know for this case is that the sum of the internal angles of a triangle is 180 °
We then have the following equation that is given by:
(2x) + (3x) + (4x) = 180
Clearing x we have:
9x = 180
x = 180/9
x = 20
Therefore we have:
m∠A = (40) °
m∠B = (60) °
m∠C = (80) °
Answer:
B) m∠B = 60 °

6 0

3 years ago

Compare square root of one hundred eighty and one hundred two eighths using <, >, or =.

olga2289 [7]

Converting the mixed number to a decimal, the correct comparison of the numbers is given as follows:

$\sqrt{180} > \sqrt{100 \frac{2}{8}}$

<h3>What is a mixed number?</h3>

A mixed number is represented by an integer part and a fractional part, as follows:

a b/c.

In which:

a is the integer part.

b/c is the fractional part.

In this problem, the numbers are given as follows:

$\sqrt{180}, \sqrt{100 \frac{2}{8}}$

The mixed number is:

100 and 2/8 = 100 + 0.25 = 100.25.

The square root is an increasing function, hence the higher the input, the higher the square root, as 180 > 100 the comparison is:

$\sqrt{180} > \sqrt{100 \frac{2}{8}}$

More can be learned about mixed numbers at brainly.com/question/1746829

#SPJ1

6 0

2 years ago

Solve <img src="https://tex.z-dn.net/?f=%5Csf%20%5Cdfrac%7B1%7D%7Bp%7D%20%2B%20%5Cdfrac%7B1%7D%7Bq%7D%20%2B%20%5Cdfrac%7B1%7D

Nostrana [21]

Answer:

$\displaystyle \begin{cases} \displaystyle {x} _{1} = - p \\ \displaystyle x _{2} = - q \end{cases}$

Step-by-step explanation:

we would like to solve the following equation for x:

$\displaystyle \frac{1}{p} + \frac{1}{q} + \frac{1}{x} = \frac{1}{p + q + x}$

to do so isolate $\frac{1}{x}$ to right hand side and change its sign which yields:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{1}{p + q + x} - \frac{1}{x}$

simplify Substraction:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{x - (q + p + x)}{x(p + q + x)}$

get rid of only x:

$\displaystyle \frac{1}{p} + \frac{1}{q} = \frac{ - (q + p )}{x(p + q + x)}$

simplify addition of the left hand side:

$\displaystyle \frac{q + p}{pq} = \frac{ - (q + p )}{x(p + q + x)}$

divide both sides by q+p Which yields:

$\displaystyle \frac{1}{pq} = \frac{ -1}{x(p + q + x)}$

cross multiplication:

$\displaystyle x(p + q + x) = - pq$

distribute:

$\displaystyle xp + xq + {x}^{2} = - pq$

isolate -pq to the left hand side and change its sign:

$\displaystyle xp + xq + {x}^{2} + pq = 0$

rearrange it to standard form:

$\displaystyle {x}^{2} + xp + xq + pq = 0$

now notice we end up with a quadratic equation therefore to solve so we can consider factoring method to use so

factor out x:

$\displaystyle x( {x}^{} + p ) + xq + pq = 0$

factor out q:

$\displaystyle x( {x}^{} + p ) +q (x + p)= 0$

group:

$\displaystyle ( {x}^{} + p ) (x + q)= 0$

by Zero product property we obtain:

$\displaystyle \begin{cases} \displaystyle {x}^{} + p = 0 \\ \displaystyle x + q= 0 \end{cases}$

cancel out p from the first equation and q from the second equation which yields:

$\displaystyle \begin{cases} \displaystyle {x}^{} = - p \\ \displaystyle x = - q \end{cases}$

and we are done!

3 0

3 years ago

Solve 1/4 divided by 3

zysi [14]

The anwser is 0.083 a bunch of threes follow but the aren't important all you need to do is round which that should be rounded enough.

6 0

3 years ago

Read 2 more answers