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3 years ago

Help pls i’m very confused

Mathematics

1 answer:

Andre45 [30]3 years ago

5 0

Hello,

A=(1,2) ==> A'=(1,2)+(1,1)=(2,3)

B=(6,2) ==> B'=(6,2)+(1,1)=(7,3)

C=(4,4) ==> C'=(4,4)+(1,1)=(5,5)

D=(1,4) ==> D'=(1,4)+(1,1)=(2,5)

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I need help ASAP <br> Integrated math II

Molodets [167]

Answer:

$\boxed{ \bold{ \sf{x = 16}}}$

$\boxed{ \bold{ \sf{m < AFD = 82}}}$

Step-by-step explanation:

$\sf{5x + 18 = 3x + 50}$

( Being vertically opposite angles)

Vertically opposite angles are always equal.

Move variable to L.H.S and change it's sign

Similarly, Move constant to R.H.S and change it's sign

⇒ $\sf{5x - 3x = 50 - 18}$

Collect like terms

⇒ $\sf{2x = 50 - 18}$

Subtract 18 from 50

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Divide both sides of the equation by 2

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Calculate

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The value of x is 16

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plug the value of x

⇒ $\sf{m < AFD + 5 \times 16 + 18 = 180}$

Multiply the numbers

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Add the numbers

⇒ $\sf{m < AFD + 98 = 180}$

Move constant to R.H.S and change it's sign

⇒ $\sf{m < AFD = 180 - 98}$

Subtract 98 from 180

⇒ $\sf{m < AFD = 82}$

Value of m<AFD = 82

Hope I helped!

Best regards!!

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nlexa [21]

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