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NISA [10]
3 years ago
6

No link nor file pease help im crying about these questions

Mathematics
2 answers:
atroni [7]3 years ago
7 0

Answer:

Step-by-step explanation:

lora16 [44]3 years ago
5 0

Answer:

7

Step-by-step explanation:

10.5*2/3= 3.5*2=7

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4. A survey found that of 26 food restaurants, 13 were pizza parlours, 9 did not sell alcohol, and 7 were pizza
ICE Princess25 [194]

Answer: 16/13

Step-by-step explanation:

Facts:  

Total: 26 restaurants

Pizza parlors: 13

9/13 do not sell alcohol

7/13 do not sell alcohol

Total probability (not serving alcohol): 16/13

8 0
2 years ago
The Olympic-size pool at the recreational center is a right rectangular prism 50\, \text{m}50m50, start text, m, end text long a
frez [133]

Answer:

The depth of the water in the pool is 2.4 metres

Step-by-step explanation:

The Volume of Water in the Pool= 3000m³

Length of the Pool=50m

Width of the Pool=25m

Height=?

Volume of a Rectangular Prism= Length X Width X Height

3000= 50 X 25 X Height

3000= 1250H

H=3000/1250

Therefore, the Height of water in the pool = 2.4m

The water in the pool is 2.4 metres deep.

5 0
4 years ago
Find the unit price of 60lbs of honey for $123.99. Round your answer to the nearest cent if necessary.
astraxan [27]
The unit price is $2.07 per lb (pound).
6 0
3 years ago
Read 2 more answers
Using Cramer’s Rule, what is the value of y in the system of linear equations below?
Vadim26 [7]

for the system of equations

a_1x+b_1y=c_1 \\a_2x+b_2y=c_2

the three matrices needed to use Cramer's Rule are:

D=\left[\begin{array}{cc}a_1&b_1\\a_2&b_2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}c_1&b_1\\c_2&b_2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}a_1&c_1\\a_2&c_2\end{array}\right].

To use Cramer's Rule we have to calculate the three determinants listed below of the matrices listed below.

D=\left[\begin{array}{cc}2&5\\-3&-2\end{array}\right] \\\\D_x=\left[\begin{array}{cc}-13&5\\3&-2\end{array}\right] \\\\D_y=\left[\begin{array}{cc}2&-13\\-3&3\end{array}\right] .

The value of the determinants are shown below.

det(D)=(2)(-2)-(-3)(5)=-4+15=11\\det(D_x)=(-13)(-2)-(3)(5)=26-15=11\\det(D_y)=(2)(3)-(-3)(-13)=6-39=-33\\

The value of y is \frac{det(D_y)}{det(D)}=-\frac{33}{11} =-3..

3 0
4 years ago
Each bowling ball weighs 7.3*10^3 grams. The bowling alley has 2.0*10^2 bowling balls. How much do they all weigh, combined? Exp
Alexandra [31]

Answer:

1.46 x 10⁶g

Step-by-step explanation:

Given parameters:

Weight of each bowling ball  = 7.3 x 10³g

Number of balls in the bowling alley = 2.0 x 10²bowling balls

Unknown

The weight of the balls in the alley  = ?

Solution:

To find the weight of the balls in the alley, multiply the mass of each balls with the total number of balls;

 Weight of the balls = 7.3 x 10³ x 2.0 x 10²

 Weight of the balls  = (7.3 x 2.0) x 10³⁺²

 Weight of the balls  = 14.6 x 10⁵g

 Therefore, the weight of the balls  = 1.46 x 10⁶g

3 0
3 years ago
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