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Damm [24]
3 years ago
5

Find the discrimanant and the number of real roots for this equation 9x^2+12x+4=0

Mathematics
1 answer:
castortr0y [4]3 years ago
7 0

For this case we have that by definition, the discriminant of a quadratic equation ax ^ 2 + bx + c = 0, is given by:

d = b ^ 2-4 (a) (c)

d> 0: Two different real roots

d = 0: Two equal real roots

d: Two different complex roots

If we have 9x ^ 2 + 12x + 4 = 0, then:

a = 9\\b = 12\\c = 4

Substituting the values:

d = 12 ^ 2-4 (9) (4)\\d = 144-144\\d = 0

Thus, we have two equal real roots.

ANswer:

We have two equal real roots.

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Solve the equation 2/3 x = 6
joja [24]

Answer: x = 9

Step-by-step explanation: divide 2/3x by 2 and do that to both sides to get 1/3x = 3 then multiply by 3 to get the whole x. multiply on both sides to get x = 9.

3 0
3 years ago
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What is the probability of rolling a dice at most 3 times until a 6 occurs
IRISSAK [1]

Answer:

Probablity of getting six in at most three roll= 0.199.

Step-by-step explanation:

Given: Dice rolled at most 3 times untill a 6 occurs.

First, finding the probablity of getting 6 in a dice if rolled once.

Probablity= \frac{chances\ of\ occurance}{Total\ number\ of\ event}

We know, dice have six side, therefore, total number of event will be 6.

∴ Probablity of getting six in one roll= \frac{1}{6}

As given, Dice is rolled at most 3 times.

Now, finding the probablity of getting 6 in a dice if rolled 3 times.

∴ Probablity of getting six in three roll= \frac{1}{6}+(\frac{1}{6})^{2} +(\frac{1}{6})^{3}

⇒ Probablity of getting six in three roll=  \frac{1}{6}+\frac{1}{36} +\frac{1}{216}

Taking LCD 216

⇒Probablity of getting six in three roll= \frac{1\times 36+ 6\times 1+1}{216}

⇒Probablity of getting six in three roll= \frac{43}{216}

∴Probablity of getting six in three roll=0.199

           

3 0
4 years ago
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Answer:

4.) ET is perpendicular to plane BAT

Step-by-step explanation:

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3 years ago
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Dahasolnce [82]

Answer:

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Step-by-step explanation:

5 0
3 years ago
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A magician is performing for an audience of 32 men and 20 women. He selects a volunteer from the audience, has the volunteer sta
g100num [7]
The correct answer is A) 37.4%.

The probability that the first volunteer is a man would be 32/52, since there are 32 men out of 52 people.  The probability that the second volunteer would also be a man would be 31/51, since there is 1 fewer man and 1 fewer person total to choose from.

32/51(31/51) = 992/2652 = 0.374 = 37.4%.
8 0
4 years ago
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