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Volgvan
3 years ago
7

tara made a snack mix with 3/4 cup of rice crackers and 2/3 cup of pretzels. she then ate 5/8 cup of the mix for lunch. how much

of the snack mix is left
Mathematics
2 answers:
grandymaker [24]3 years ago
8 0
First you add 3/4 and 2/3 you but then do 3/4 2/3 you think what the both can go to is 12 the dominator is 12 then you time it by 3,4 because they both go to 12 then the 3 will be time 3 because 4 x 3 = 12 then you do it the top so 3x3 = 9 9/12 then you do the next one is2/3 do the same then will get 8/12 then you can subtract it 9/12 - 8/12 will gave you 1/12
sergejj [24]3 years ago
5 0
You will have 1/12 is your answer
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Your answer must be simplified.
JulijaS [17]

Answer:

The simplified form is x\geq -99.

Step-by-step explanation:

Given : Expression \frac{x}{3}\geq -33

To find : The simplified expression ?

Solution :

Expression \frac{x}{3}\geq -33

Multiply 3 both side,

\frac{x}{3}\times 3\geq -33\times 3

x\geq -99

Therefore, the simplified form is x\geq -99.

8 0
3 years ago
PLZ HELP ME I HAVE 3 MORE MINUTES
Svetradugi [14.3K]

Answer:

3

Step-by-step explanation:

(6 + 2 x 6)/(15 - 11 + 2)

(6 + 12)/(4 + 2)

18/6

3

8 0
3 years ago
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Add or subtrack<br>1. -16 +21<br>2.-13--12<br>3.-23-(-8)​
konstantin123 [22]

Answer:

1. subtract

2.  add

3. add

4 0
3 years ago
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Beneze recipe for granola bars close for 3 1/2 cups of oatmeal he only has 16 cup scoop how many scoops of oatmeal he need for t
LUCKY_DIMON [66]
16/3 1/2= 7/32. so you would measure 7/32 on the 16 cup scoop
7 0
3 years ago
The vertex of this parabola is at (2,-1) when the y value is 0 and then x value is 5 what is the coefficient of the squared term
Darina [25.2K]

\bf ~~~~~~\textit{parabola vertex form} \\\\ \begin{array}{llll} \stackrel{\textit{we'll use this one}}{y=a(x- h)^2+ k}\\\\ x=a(y- k)^2+ h \end{array} \qquad\qquad vertex~~(\stackrel{2}{ h},\stackrel{-1}{ k}) \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=2\\ k=-1 \end{cases}\implies y=a(x-2)^2-1 \\\\\\ \textit{we also know that } \begin{cases} y=0\\ x=5 \end{cases}\implies 0=a(5-2)^2-1\implies 1=9a \\\\\\ \cfrac{1}{9}=a\qquad therefore\qquad \boxed{y=\cfrac{1}{9}(x-2)^2-1}


now, let's expand the squared term to get the standard form of the quadratic.


\bf y=\cfrac{1}{9}(x-2)^2-1\implies y=\cfrac{1}{9}(x^2-4x+4)-1 \\\\\\ y=\cfrac{1}{9}x^2-\cfrac{4}{9}x+\cfrac{4}{9}-1\implies \stackrel{its~coefficient}{y=\stackrel{\downarrow }{\cfrac{1}{9}}x^2-\cfrac{4}{9}x-\cfrac{5}{9}}

4 0
3 years ago
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