The answer to the question above is 3
Answer:
Ka = 4.9 x 10ˉ⁴
Explanation:
HOAc ⇄ H⁺ + OAcˉ
Ka = [H⁺][OAcˉ]/[HOAc]
Given pH = 2.58 => [H⁺] = [OAcˉ] = 10ˉ²∙⁵⁸ = 2.63 x 10ˉ³M
Ka = (2.63 x 10ˉ³)²/(0.0142) = 4.9 x 10ˉ⁴
NaOH but you didnt give options
Answer:
Answer is A
Explanation:
Now we know that an atom wants to complete its outer shell while keeping electrons in pairs of two now in A there are four electrons which which can be ejected while in B will want to accept 3 electrons to complete its shell as ejecting five will take lot of energy similar case will be for C,D and E which would want to accept 2,1,0 electrons respectively