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tatyana61 [14]
3 years ago
9

1. Balance this reaction: Fe2O3(s) + C(s) → Fe(s) + CO2(g)

Chemistry
1 answer:
MA_775_DIABLO [31]3 years ago
4 0
<span>2Fe2O3(s) + 3C(s) →4 Fe(s) + 3CO2(g)
                       3 mol                      3mol
                       4 mol                      x mol
x=4*3/3= 4.0 mol

</span>2Fe2O3(s) + 3C(s) →4 Fe(s) + 3CO2(g)<span>
2 mol              3 mol
14 mol            x mol

x=14*3/2= 21.0 mol</span>
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Answer:

seven on the ph scale is the neutral point

Explanation:

The range goes from 0 - 14, with 7 being neutral. pHs of less than 7 indicate acidity, whereas a pH of greater than 7 indicates a base. pH is really a measure of the relative amount of free hydrogen and hydroxyl ions in the water.

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What is the correct name for the compound, P2O5?
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How many moles of MgO are produced when .250 mol of Mg reacts completely with O2
nignag [31]

Answer:

0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂

Explanation:

In first place, the balanced reaction between Mg and O₂ is:

2 Mg + O₂ ⇒ 2 MgO

By stoichiometry of the reaction (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of reactants and products participate in the reaction:

  • Mg: 2 moles
  • O₂: 1 mole
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Then you can apply the following rule of three: if by reaction stoichiometry 2 moles of Mg produce 2 moles of MgO, 0.250 moles of Mg, how many moles of MgO will they form?

moles of MgO=\frac{0.250 moles of Mg*2 moles of MgO}{2 moles of Mg}

moles of MgO= 0.250

<u><em>0.250 moles of MgO are produced when 0.250 mol of Mg reacts completely with O₂</em></u>

3 0
3 years ago
For the reaction 2NH3(g) + 2O2(g)N2O(g) + 3H2O(l) H° = -683.1 kJ and S° = -365.6 J/K The standard free energy change for the rea
BlackZzzverrR [31]

Answer:

\Delta G^{0} = -457.9 kJ and reaction is product favored.

Explanation:

The given reaction is associated with 2 moles of NH_{3}

Standard free energy change of the reaction (\Delta G^{0}) is given as:

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So, \Delta G^{0}=(-683.1\times 10^{3})J-(273K\times -365.6J/K)=-583291.2J

So, for the reaction of 1.57 moles of NH_{3}, \Delta G^{0}=(\frac{1.57}{2})\times -583291.2J=-457883.592J=-457.9kJ

As, \Delta G^{0} is negative therefore reaction is product favored under standard condition.

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What is the molar mass of C4H10
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