1. Balance this reaction: Fe2O3(s) + C(s) → Fe(s) + CO2(g)
1 answer:
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Answer:
=> 2.8554 g/mL
Explanation:
To determine the formula to use in solving such a problem, you have to consider what you have been given.
We have;
mass (m) = 16.59 g
Volume (v) = 5.81 mL
From our question, we are to determine the density (rho) of the rock.
The formula:
Substitute the values into the formula:
= 2.8554 g/mL
Therefore, the density (rho) of the rock is 2.8554 g/mL.
Answer:
2.24 L of hydrogen gas, measured at STP, are produced.
Explanation:
Given, Moles of magnesium metal, = 0.100 mol
Moles of hydrochloric acid, = 0.500 mol
According to the reaction shown below:-
1 mole of Mg reacts with 2 moles of
0.100 mol of Mg reacts with 2*0.100 mol of
Moles of must react = 0.200 mol
Available moles of = 0.500 moles
Limiting reagent is the one which is present in small amount. Thus, is limiting reagent.
The formation of the product is governed by the limiting reagent. So,
1 mole of on reaction forms 1 mole of
0.100 mole of on reaction forms 0.100 mole of
Mole of = 0.100 mol
At STP,
Pressure = 1 atm
Temperature = 273.15 K
Volume = ?
Using ideal gas equation as:
where,
P is the pressure
V is the volume
n is the number of moles
T is the temperature
R is Gas constant having value = 0.0821 L.atm/K.mol
Applying the equation as:
1 atm × V L = 0.100 × 0.0821 L.atm/K.mol × 273.15 K
<u>⇒V = 2.24 L</u>
2.24 L of hydrogen gas, measured at STP, are produced.