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Svetllana [295]
3 years ago
15

If a substance has a density of 1.345g / mL , how many grams would the substance weigh if the sample has a volume of 22.1 ml?

Chemistry
1 answer:
spayn [35]3 years ago
4 0

Answer:

Mass of substance = 29.7245 gram

Explanation:

Given:

Density of substance = 1.345 g / ml

Volume of substance = 22.1 ml

Find:

Mass of substance

Computation:

Mass = Density x Volume

Mass of substance = Density of substance x Volume of substance

Mass of substance = 1.345 x 22.1

Mass of substance = 29.7245 gram

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An object with a mass of 3.2kg has a force of 16.3 newtons to the right and 6.7 newtons to the left applied to it. What is the r
Pepsi [2]

Answer:

3m/s²

Explanation:

Given parameters:

Mass of object  = 3.2kg

Force to the right = 16.3N

Force to the left  = 6.7N

Unknown:

Acceleration of the object  = ?

Solution:

To solve this problem, we use newtons second law of motion;

   Net force  = mass x acceleration

 Net force on object  = Force to the right  - Force to the left

 Net force  = 16.3N  - 6.7N  = 9.6N

    So;

         9.6  = 3.2 x a

              a = \frac{9.6}{3.2}   = 3m/s²

7 0
2 years ago
In calcium fluoride, what is the closets noble gas that each ion becomes?
alekssr [168]
Calcium fluoride: CaF₂
Ca(2+) >>> Ar (argon)
F(-) >>> Ne (neon)
4 0
3 years ago
Are all molecules of a particular substance alike?
STALIN [3.7K]

Answer:

Yes.

Explanation:

Yes, all molecules of a particular substance are similar or alike if the substance has similar shape and structure. Molecule is made up of two or more atoms having no charge on them and the atoms present in it make bonds with each other. For example, water is made of similar molecules i. e. two hydrogen atom and one oxygen atom bonded together with a covalent bond.

4 0
3 years ago
Hydroxylamine is a weak molecular base with kb = 6.6 x 10-9. what is the ph of a 0.0500 m solution of hydroxylamine?
7nadin3 [17]
Answer is: pH of hydroxylamine solution is 9,23.

Kb(NH₂OH) = 1,8·10⁻⁵<span>.
c</span>₀(NH₂OH)<span> = 0,0500 M = 0,05 mol/L.
c(NH</span>₂⁺) = c(OH⁻) = x.

c(NH₂OH<span>) = 0,05 mol/L - x.
Kb = c(NH</span>₂⁺) · c(OH⁻) / c(NH₂OH).

0,0000000066 = x² /  (0,05 mol/L - x). 

solve quadratic equation: x = c(OH⁻) = 0,000018 mol/L.<span>
pOH = -log(</span>0,000018 mol/L) = 4,74.<span>
pH = 14 - 4,74 = 9,23.</span>


4 0
3 years ago
(c) O2 gas is transferred from a 3 L vessel containing oxygen at 4 atm to an evacuated 20 L vessel at a constant temperature of
Fudgin [204]

Answer:

After the transfer the pressure inside the 20 L vessel is 0.6 atm.

Explanation:

Considering O2 as an ideal gas, it is at an initial state (1) with V1 = 3L and P1 = 4 atm. And a final state (2) with V2 = 20L. The temperature remain constant at all the process, thus here applies the Boyle-Mariotte law. This law establishes that at a constant temperature an ideal gas the relationship between pressure and volume remain constant at all time:

P x V = k

Therefore, for this problem the step by step explanation is:

P_{1} xV_{1} = P_{2} xV_{2}

Clearing P2 and replacing

P_{2}= \frac{P_{1} xV_{1}}{V_{2} } = \frac{4atmx3L}{20L} = 0.6atm

7 0
3 years ago
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