1. If a person's mass is 56 kg, what is this weight in pounds? 56kg
1 answer:
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Answer:
The methyl group will already be present
Explanation:
You want to make 1-methyl-4-nitrobenzene.
The question is, "Do I start with the methyl group on the ring and then nitrate, or do I start with the nitro group on the ring and then add the methyl group?"
The methyl group is activating and ortho, para directing.
The nitro group is deactivating and meta directing.
You want a para-substituted product, so you choose to nitrate toluene, as in the reaction scheme below.
Hello!
We have the following data:
Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)
To move on, we must transform the area of 50 ft² in cm², let's see:
1 ft² ------- 929,0304 cm²
50 ft² ----- A
In the same way, we will convert the mass of 8.5 oz in grams, see:
1 oz -------- 28,3495 g
8,5 oz ------- m
Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:
The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)
In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:
We will convert to millimeters, going through a decimal place on the right
Hope this helps! :))
We have the following data:
Area (A) = 50 square feet
Mass (m) = 8.5 ounces
Density (d) = 2.70 g/cm³
Volume (V) = ?
Thickness (T) =? (in mm)
To move on, we must transform the area of 50 ft² in cm², let's see:
1 ft² ------- 929,0304 cm²
50 ft² ----- A
In the same way, we will convert the mass of 8.5 oz in grams, see:
1 oz -------- 28,3495 g
8,5 oz ------- m
Knowing that the density is 2.70 g/cm³ and the mass is 240.97075 g, we will find the volume, applying the data in the density formula we have:
The statement wants to find the thickness of the packaging, for this we have some important data, such as: V (volume) = 89,25 cm³ and Area (A) = 46451,52 cm² and T (thickness) =? (in mm)
In the calculations of Costs in Surface Treatment of a part within the flat geometry, we will use the following formula:
We will convert to millimeters, going through a decimal place on the right
Hope this helps! :))
From a stock solution of 3.00 m nitric acid, 9.391 ml of stock solution is needed to create a 0.161 m nitric acid solution, which has a total volume of 175 ml of the diluted solution.
A chemical reagent is present in vast quantities as a stock solution. It has a uniform concentration. Examples of typical stock solutions in laboratories are nitric acid and hydrochloric acid. These play a critical role in creating the titration-related solution preparations.
We know the formula for dilution type problems
M1 VI = M2 V 2
Where,
M, = initial molarity
V , = initial Volume
M2 = final molarity
V 2 = final Volume
Hene given -
M, = 3.00 M
VI = ?
M2 = 0.161M
V 2 = 175 ml
Accordingly ' MI V1 = M2 V 2
V1 =
V1= (0.161M*175ml)/ 3.00M
v1 = 9.391
The required volume of Stock solution is 9.391ml.
Learn more about Stock solution here
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