Answer:
ABCD is not a parallelogram
Step-by-step explanation:
Use the distance formula to determine whether ABCD below is a parallelogram. A(-3,2) B(-3,3) C (5,-3) D (-1.-5)
We have to find the length of the sides of the parallelogram using the formula below
= √(x2 - x1)² + (y2 - y1)² when given vertices (x1, y1) and (x2, y2)
For side AB
A(-3,2) B(-3,3)
= √(-3 -(-3))² + (3 -2)²
= √0² + 1²
= √1
= 1 unit
For side BC
B(-3,3) C (5,-3)
= √(5 -(-3))² + (-3 -3)²
= √8² + -6²
= √64 + 36
= √100
= 10 units
For side CD
C (5,-3) D (-1.-5)
= √(-1 - 5)² + (-5 - (-3))²
= √-6² + -2²
= √36 + 4
= √40 units
For sides AD
A(-3,2) D (-1.-5)
= √(-1 - (-3))² + (-5 -2)²
= √(2² + -7²)
= √(4 + 49)
= √53 units
A parallelogram is a quadrilateral with it's opposite sides equal
From the above calculation
Side AB ≠ CD
BC ≠ AD
Therefore, ABCD is not a parallelogram
Answer: The area of the new parallelogram is multiplied by 18
Step-by-step explanation: Let the base and the height of the original parallelogram be ' x '
Base of the parallelogram = x
Height of the parallelogram = x
Area of parallelogram = l × b = lb
= x × x = x²
∴ Area of the original parallelogram = x²
∴ The base is multiplied by 3 = 3x
The height is multiplied by 6 = 6x
∴ Area of new parallelogram = 3x × 6x = 18x²
∴ The area of the new parallelogram is multiplied by = 18x²/ x²
= 18
<u><em>Please mark this as brainliest</em></u>
Answer:
9 times older.
Step-by-step explanation: Mark brainliest if this helps.
Answer:
I guess option c is the answer
Answer:
a) 
b) 
c) Mary's score was 241.25.
Step-by-step explanation:
Problems of normally distributed samples can be solved using the z-score formula.
In a set with mean 
and standard deviation 
, the zscore of a measure X is given by:
The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.
In this problem, we have that:
a) Find the z-score of John who scored 190
b) Find the z-score of Bill who scored 270
c) If Mary had a score of 1.25, what was Mary’s score?
Mary's score was 241.25.
