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allochka39001 [22]
2 years ago
14

Korri took 5 breaks in 8 hours. How many breaks does she take per hour?

Mathematics
2 answers:
gregori [183]2 years ago
8 0
The answer is 40 because question is 5x8=40
topjm [15]2 years ago
6 0

Answer:

1.6?

Step-by-step explanation:

Hope this helped, so sorry, but this is confusing. I divided the two numbers both ways which was supposed to give me the answer? Was there a number line or something to go with it?

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Seven years ago, kodi found a box of old baseball cards in the garage. since then, he has added a consistent number of cards to
Katena32 [7]
(3,52)(7,108)
slope = (108 - 52) / (7 - 3) = 56/4 = 14

y = mx + b
slope(m) = 14
(3,52)...x = 3 and y = 52
sub and find b, the y int (the original amount of cards)
52 = 3(14) + b
52 = 42 + b
52 - 42 = b
10 = b

so ur equation is y = 14x + 10....with x being the number of years and y being the total cards. <== ur equation is y = 14x + 10

He started with 10 cards....and has been adding 14 cards every year.

so after 10 years...
y = 14(10) + 10
y = 140 + 10
y = 150 <== after 10 years, he will have 150 cards
8 0
3 years ago
ANSWER THE QUESTIONS PLEASE IT IS ON BEARING
artcher [175]

9514 1404 393

Answer:

  (i) x° = 70°, y° = 20°

  (ii) ∠BAC ≈ 50.2°

  (iii) 120

  (iv) 300

Step-by-step explanation:

(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.

  x = 70

The angle marked y° is the supplement to the one marked 160°.

  y = 20

__

(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...

  tan(∠BAC) = BC/BA = 120/100 = 1.2

  ∠BAC = arctan(1.2) ≈ 50.2°

__

(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.

  bearing of C = 70° +50.2° = 120.2°

The three-digit bearing of C from A is 120.

__

(iv) The bearing of A from C is 180 added to the bearing of C from A:

  120 +180 = 300

The three-digit bearing of A from C is 300.

8 0
3 years ago
Simplify.<br><br> 5 - {-(-2)}<br><br> A)-3<br> B) 3<br> C)-7<br> D) 7
Fed [463]
<span>5 - {-(-2)}
</span>5 - {+2} (negative + negative = positive)
<span>5 - 2 (negative + positive = negative)
</span>3
5 0
2 years ago
Mr. Wallace needs to divide his class or 23 students into 9 groups. Each group can have two or three students. If a is the numbe
IRINA_888 [86]

Answer:

d)  Mr.Wallace can use the following equations:

    a + b = 9

   2 a + 3 b = 23

Step-by-step explanation:

Here, the total number of students = 23

Number of groups = 9

Each group can have 2 or 3 students.

a is the number of  groups of 2.

⇒ Total students in a groups  = a x (Number of  student in each group)

= a x 2 = 2 a

b is the number of groups of 3

⇒ Total students in b groups  = b x (Number of  student in each group)

= b x 3 = 3 b

So, according to the question:

Total number of groups formed = 9

⇒ a + b = 9

Total number of students  = 23

or Number of students in  ( a  group + b group ) = 23

⇒ 2 a + 3 b = 23

Hence, Mr.Wallace can use the following equations:

a + b = 9

2 a + 3 b = 23

6 0
3 years ago
7 is a factor of <br> a 28<br> b 16<br> c 11<br> d 4
Blababa [14]

Answer:

a) 28

Step-by-step explanation:

4 0
2 years ago
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