(3,52)(7,108)
slope = (108 - 52) / (7 - 3) = 56/4 = 14
y = mx + b
slope(m) = 14
(3,52)...x = 3 and y = 52
sub and find b, the y int (the original amount of cards)
52 = 3(14) + b
52 = 42 + b
52 - 42 = b
10 = b
so ur equation is y = 14x + 10....with x being the number of years and y being the total cards. <== ur equation is y = 14x + 10
He started with 10 cards....and has been adding 14 cards every year.
so after 10 years...
y = 14(10) + 10
y = 140 + 10
y = 150 <== after 10 years, he will have 150 cards
9514 1404 393
Answer:
(i) x° = 70°, y° = 20°
(ii) ∠BAC ≈ 50.2°
(iii) 120
(iv) 300
Step-by-step explanation:
(i) Angle x° is congruent with the one marked 70°, as they are "alternate interior angles" with respect to the parallel north-south lines and transversal AB.
x = 70
The angle marked y° is the supplement to the one marked 160°.
y = 20
__
(ii) The triangle interior angle at B is x° +y° = 70° +20° = 90°, so triangle ABC is a right triangle. With respect to angle BAC, side BA is adjacent, and side BC is opposite. Then ...
tan(∠BAC) = BC/BA = 120/100 = 1.2
∠BAC = arctan(1.2) ≈ 50.2°
__
(iii) The bearing of C from A is the sum of the bearing of B from A and angle BAC.
bearing of C = 70° +50.2° = 120.2°
The three-digit bearing of C from A is 120.
__
(iv) The bearing of A from C is 180 added to the bearing of C from A:
120 +180 = 300
The three-digit bearing of A from C is 300.
<span>5 - {-(-2)}
</span>5 - {+2} (negative + negative = positive)
<span>5 - 2 (negative + positive = negative)
</span>3
Answer:
d) Mr.Wallace can use the following equations:
a + b = 9
2 a + 3 b = 23
Step-by-step explanation:
Here, the total number of students = 23
Number of groups = 9
Each group can have 2 or 3 students.
a is the number of groups of 2.
⇒ Total students in a groups = a x (Number of student in each group)
= a x 2 = 2 a
b is the number of groups of 3
⇒ Total students in b groups = b x (Number of student in each group)
= b x 3 = 3 b
So, according to the question:
Total number of groups formed = 9
⇒ a + b = 9
Total number of students = 23
or Number of students in ( a group + b group ) = 23
⇒ 2 a + 3 b = 23
Hence, Mr.Wallace can use the following equations:
a + b = 9
2 a + 3 b = 23
Answer:
a) 28
Step-by-step explanation:
