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Leona [35]
3 years ago
7

Solve the quadratic function by graphing.

Mathematics
1 answer:
qaws [65]3 years ago
5 0

-4x²+16x-16=0

X=2

The choose (2,0)

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Daine simplified the expression below.
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Answer:

He did NOT apply the distributive property correctly for 8(1 + 2i)

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12. Convierte estas fracciones impropias en números mixtos:
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A. 2 1/7
B. 2 3/6
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Find the measure of angle J.<br><br>123°<br><br>237°<br><br>57°<br><br>115°
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57. You Take 180 And Subtract It From The 65 And  58 To Get Your Answer

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To find the product of (−2√20k)(5√8k3), first write using a single radical. Which expression is equivalent to the given product?
ad-work [718]

Answer:

Assuming the variable is included under the radical,

-40k²√(10)

Step-by-step explanation:

(-2\sqrt{20k})(5\sqrt{8k^3})

First we will simplify the first factor,

-2\sqrt{20k}

We will write 20 as a product of factors:

-2\sqrt{4*5k}

We know the square root of 2 is 2, so we pull a 2 out:

-2(2)\sqrt{5k}\\\\=-4\sqrt{5k}

Now we will simplify the second factor,

5\sqrt{8k^3}

We will rewrite 8 as a product of factors, as well as the variable:

5\sqrt{2*4*k^2*k}

The square root of 2 is 2, so we pull a 2 out.  Additionally, the square root of k² is k, so we pull that out:

5(2)(k)\sqrt{2k}\\\\=10k\sqrt{2k}

This gives us the product

(-4\sqrt{5k})(10k\sqrt{2k})

Multiplying the coefficients, we have

-4(10k)(\sqrt{5k})(\sqrt{2k})\\\\=-40k(\sqrt{5k})(\sqrt{2k})

Multiplying the two radicals, we have

-40k\sqrt{5k*2k}\\\\-40k\sqrt{10k^2}

The square root of k² is k, so we pull a k out, leaving

-40k(k)\sqrt{10}\\\\=-40k^2\sqrt{10}

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4 years ago
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Solve the equation. Then check your solution.
Serhud [2]

Answer: B

Step-by-step explanation: 6-4=2

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4 years ago
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