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Misha Larkins [42]
3 years ago
9

Which congruence criteria can be used directly from the information about triangles HIJ and MNO to prove IJ¯¯¯¯¯¯≅MN¯¯¯¯¯¯¯¯¯¯ b

y CPCTC? HI¯¯¯¯¯¯¯≅NO¯¯¯¯¯¯¯¯, ∠I≅∠N, ∠H≅∠O (1 point) ASA congruence AAS congruence SAS congruence HL congruence
Mathematics
1 answer:
skelet666 [1.2K]3 years ago
7 0

Answer: \overline{IJ}\cong \overline{MN}

Step-by-step explanation:

Given: In triangle HIJ and triangle MNO we have

\overline{HI}\cong \overline{NO}, \angle{I}\cong \angle{N} ,\angle{H}\cong \angle{O}

here, HI and NN are the included side between  ∠I & ∠H and ∠N and ∠O.

So , by ASA congruence rule,

ΔHIJ ≅ ΔMNO

So by CPCTC  (corresponding parts of the congruent triangles are congruent)

\overline{IJ}\cong \overline{MN}

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The area of the parallelogram is 65 square miles. Find it’s base and height. x-4 , x+4
Ne4ueva [31]

Answer:

base = b = 5

height = h = 13

Step-by-step explanation:

Given Data:

Area of Parallelogram = A = 65 miles^{2}

base = b = x -4

height = h = x+4

Formula:

A = b×h

Solution:

A = b×h

65 = (x-4)×(x+4)

65 = x^{2} - 4^{2}                               ∴ (a-b)(a+b) = a^{2} - b^{2}

65 = x^{2} - 16

x^{2} = 65 + 16

x^{2} = 81

\sqrt{x^{2} }  = \sqrt{81}

x = \sqrt{9^{2} }

x = 9

Now,

base = b = x -4 = 9-4

base = b = 5

height = h = x+4 = 9+4

height = h = 13

4 0
4 years ago
A car traveled 212 km in 5 hours what was the cars average speed
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Answer:

42.4 mph

Step-by-step explanation:

5÷212= 42.4mph (average speed)

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2 years ago
Help plz:)))I’ll mark u Brainliest
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You are then left with 114 as the sum of both the angles you need to find
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3 years ago
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