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2 years ago

In AMNO, m = 56 cm, n = 19 cm and o=57 cm. Find the measure of Zo to the nearest

Mathematics

1 answer:

irina [24]2 years ago

7 0

Answer:83.3∘

Step-by-step explanation:

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What is the constant in the expression?

Tpy6a [65]

If your answer was d) 3.6 , then you are correct!

7 0

2 years ago

We want to factor the following expression:

S_A_V [24]

Answer:

A. (U+V)^2 or (U-V)^2

Step-by-step explanation:

$9x^6 + 6x^3y + y^2 \\ \\ = {(3 {x}^{3} )}^{2} + 2.(3x^3).y +( y)^2 \\ \\ = \bigg({3 {x}^{3} } + y \bigg)^{2} \\ \\ = \bigg({3 {x}^{3} } + y \bigg) \bigg({3 {x}^{3} } + y \bigg) \\ \\ \\ \\$

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2 years ago

Determine whether a probability distribution is given. If a probability distribution is given, find its mean and standard deviat

drek231 [11]

Answer:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

Step-by-step explanation:

For this case we have the following probability distribution given:

X 0 1 2 3 4 5

P(X) 0.031 0.156 0.313 0.313 0.156 0.031

The expected value of a random variable X is the n-th moment about zero of a probability density function f(x) if X is continuous, or the weighted average for a discrete probability distribution, if X is discrete.

The variance of a random variable X represent the spread of the possible values of the variable. The variance of X is written as Var(X).

We can verify that:

$\sum_{i=1}^n P(X_i) = 1$

And $P(X_i) \geq 0, \forall x_i$

So then we have a probability distribution

We can calculate the expected value with the following formula:

$E(X) = \sum_{i=1}^n X_i P(X_i) = 0*0.031 +1*0.156+ 2*0.313+3*0.313+ 4*0.156+ 5*0.031 = 2.5$

We can find the second moment given by:

$E(X^2) = \sum_{i=1}^n X^2_i P(X_i) = 0^2*0.031 +1^2*0.156+ 2^2*0.313+3^2*0.313+ 4^2*0.156+ 5^2*0.031 =7.496$

And we can calculate the variance with this formula:

$Var(X) =E(X^2) -[E(X)]^2 = 7.496 -(2.5)^2 = 1.246$

And the deviation is:

$Sd(X) = \sqrt{1.246}= 1.116$

6 0

3 years ago

The correct Standard Form of the equation y=3/2x+3

DanielleElmas [232]

Answer:

3x-2y=-6

My mom listening to wap

6 0

3 years ago

There are 70 students in the school band. 40% of them are sixth graders, 20% are seventh graders, and the rest are eighth grader

nirvana33 [79]

The answer is 10% if There is 40% six graders and 20% seventh graders then you need 10% more to make 100% so it’s 10% eighth graders

8 0

3 years ago

Read 2 more answers