Aubrey worked at the concession stand during a recent sporting event at her high school. During the first hour of the event, she
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Let
<span>A------> (−3, −11)
B------> (6, 4)
step 1
find the slope m point A and point B
m=(y2-y1)/(x2-x1)-----> </span>m=(4+11)/(6+3)----> m=15/9---> 5/3
step 2
with m=5/3 and point B (6, 4) find the equation of a line
y-y1=m*(x-x1)-----> y-4=(5/3)*(x-6)---> y=(5/3)x-6
case <span>a. they have the same slope------> is not correct
because
</span><span>y=35x−6------> the slope m=35
</span>y=(5/3)x-6---> the slope m =5/3
case <span>b. they have the same x-intercept.----> is not correct
because
</span>the x-intercept is for y=0
y=35x−6-----> 0=35x-6----> 35x=6-----> x=6/35
the x-intercept is the point (6/35,0)
y=(5/3)x-6----> 0=(5/3)x-6----> (5/3)x=6---> x=18/5
the x-intercept is the point (18/5,0)
case <span>c. the two lines are perpendicular. do. they have the same y-intercept-----> is nor correct
because
if two lines are perpendicular
m1*m2=-1-------> </span><span>this condition is not satisfied
</span>
the y intercept is for x=0
y=35x−6-------> y=-6
the y intercept is the point (0,-6)
y=(5/3)x-6-----> y=-6
the y intercept is the point (0,-6)
they have the same y-intercept but the two lines are not perpendicular
see the attached figure
<span>A------> (−3, −11)
B------> (6, 4)
step 1
find the slope m point A and point B
m=(y2-y1)/(x2-x1)-----> </span>m=(4+11)/(6+3)----> m=15/9---> 5/3
step 2
with m=5/3 and point B (6, 4) find the equation of a line
y-y1=m*(x-x1)-----> y-4=(5/3)*(x-6)---> y=(5/3)x-6
case <span>a. they have the same slope------> is not correct
because
</span><span>y=35x−6------> the slope m=35
</span>y=(5/3)x-6---> the slope m =5/3
case <span>b. they have the same x-intercept.----> is not correct
because
</span>the x-intercept is for y=0
y=35x−6-----> 0=35x-6----> 35x=6-----> x=6/35
the x-intercept is the point (6/35,0)
y=(5/3)x-6----> 0=(5/3)x-6----> (5/3)x=6---> x=18/5
the x-intercept is the point (18/5,0)
case <span>c. the two lines are perpendicular. do. they have the same y-intercept-----> is nor correct
because
if two lines are perpendicular
m1*m2=-1-------> </span><span>this condition is not satisfied
</span>
the y intercept is for x=0
y=35x−6-------> y=-6
the y intercept is the point (0,-6)
y=(5/3)x-6-----> y=-6
the y intercept is the point (0,-6)
they have the same y-intercept but the two lines are not perpendicular
see the attached figure
