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Harlamova29_29 [7]
3 years ago
6

A tow rope will break if the tension in it exceed 1500N. It is used to tow a 600 kg car along level ground. What is the largest

acceleration the rope can give to the car ?
Physics
1 answer:
Sati [7]3 years ago
6 0

Answer:

2.5 m/s²

Explanation:

From the question

F = ma................... Equation 1

Where F = Tension, m = mass, a = acceleration of the car

make a the subject of the equation

a = F/m.................. Equation 2

Given: F = 1500 N, m = 600 kg

Substitute these values into equation 2

a = 1500/600

a = 2.5 m/s²

Hence the largest acceleration the rope can give to the car is 2.5 m/s²

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World-class sprinters can accelerate out of the starting blocks with an acceleration that is nearly horizontal and has magnitude
Karo-lina-s [1.5K]

Answer:

A. The force exerted by the sprinter must be  9.6 × 10² N.

B. The force that propels the sprinter is exerted by the blocks.

Explanation:

Hi there!

Let´s begin with part B:

The sprinter exerts a force on the blocks and, as a reaction, the blocks exert a force on the sprinter that is of equal magnitude but opposite direction (Newton´s third law). This reaction of the blocks causes the acceleration of the sprinter.

Part A

The force exerted by the blocks can be calculated using Newton´s second law:

F = m · a

Where:

F = exerted force.

m = mass of the object being accelerated.

a = acceleration of the object after applying the force on the object.

F = m · a

F = 64 kg · 15 m/s²

F = 9.6 × 10² N

8 0
3 years ago
There are four major auto routes from boston to detroit and six from detroit to los angeles. how many major auto routes are ther
Ilia_Sergeevich [38]
For each route from Boston to Detroit, there are 6 possible routes to Los Angeles.
Therefore if there are 4 routes from Boston to Detroit, the number of routes from Boston to Los Angeles is
4*6 = 24
The diagram shown below illustrates the possible routes.

Answer: 24

6 0
3 years ago
1. You are designing a new solenoid and experimenting with material for each turn. The particular turn you are working with is a
svetoff [14.1K]

Answer:

Explanation:

1 ) Magnetic field due to a circular coil carrying current

= μ₀I / 2r

I is current , r is radius of the wire , μ₀ = 4π x 10⁻⁷

= 4π x 10⁻⁷ x 15 / (2 x 3.5 x 10⁻²)

= 26.9 x 10⁻⁵ T

2 )

Negative z direction .

The direction of magnetic field due to a circular coil having current is known  

with the help of screw rule or right hand thumb rule.

3 )

If we decrease the radius the magnetic field will:__increase _____.

A. Increase.

Magnetic field due to a circular coil carrying current

B = μ₀I / 2 r

Here r is radius of the coil . If radius decreases magnetic field increases.

So magnetic field will increase.

4 0
3 years ago
WILL MARK BRAINLIEST <br> How do you convert Farenheit to Celcius<br> and Celcius to Farenheit
olya-2409 [2.1K]

Answer:

F= \frac{9}{5}C+32

C=\frac{5}{9}(F-32)

F stands for farenheit

C stands for celcius

Explanation:

3 0
4 years ago
Read 2 more answers
A 7.0 mm -diameter copper ball is charged to 40 nC. What fraction of its electrons have been removed? The density of copper is 8
mylen [45]

Answer:

f = 2.6 \times 10^{-13}

Explanation:

Let the mass of copper ball is "m" gram

now the total number of copper atom present in the ball is given as

N = \frac{m}{29} \times 6.02 \times 10^{23}

now the total number of electrons in one copper atom is 29

so total number of electrons in given sample of copper ball is

N_e = m(6.02 \times 10^{29})

now diameter of the ball is 7.0 mm

density of the ball = 8900 kg/m^3

now we have

m = (\frac{4}{3}\pi r^3)(8900)

m = (\frac{4}{3}\pi(\frac{0.007}{2})^3)(8900)

m = 1.6 gram

now we have

N_e = 9.63 \times 10^{23}

now the charge on the copper ball is 40 nC

so the number of electrons removed

Q = ne

40 \times 10^{-9} = n(1.6 \times 10^{-19}

n = 2.5 \times 10^{11}

so the fraction of number of electrons removed is given as

f = \frac{n}{N_e}

f = \frac{2.5 \times 10^{11}}{9.63 \times 10^{23}}

f = 2.6 \times 10^{-13}

7 0
4 years ago
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