Answer:
2.5 m/s²
Explanation:
From the question
F = ma................... Equation 1
Where F = Tension, m = mass, a = acceleration of the car
make a the subject of the equation
a = F/m.................. Equation 2
Given: F = 1500 N, m = 600 kg
Substitute these values into equation 2
a = 1500/600
a = 2.5 m/s²
Hence the largest acceleration the rope can give to the car is 2.5 m/s²
I think that's Newton's second law of motion
f = m(v-u)
________
t
since a = (v-u)t
f = ma
The final momentum is 20.00 kg*m/s
The momentum of an object is given by:
where
m is the mass of the object
v is its velocity
For the object in the problem, the initial momentum is
Then, the mass is doubled:
m' = 2m
And the velocity is also doubled:
v' = 2v
So, the new momentum will be:
So, the final momentum is 4 times the initial momentum.
Learn more about momentum:
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0.0928J
the pulling force of spring F=-kx
where x is the displacement from equilibrium position.
energy stored:
*** Its fine if you know nothing about calculus. Just apply the equation
where U is the potential energy of the spring***
put x=0.150, × = 0.0928J (corr. to 3 sig. fig.)