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Harlamova29_29 [7]
3 years ago
6

A tow rope will break if the tension in it exceed 1500N. It is used to tow a 600 kg car along level ground. What is the largest

acceleration the rope can give to the car ?
Physics
1 answer:
Sati [7]3 years ago
6 0

Answer:

2.5 m/s²

Explanation:

From the question

F = ma................... Equation 1

Where F = Tension, m = mass, a = acceleration of the car

make a the subject of the equation

a = F/m.................. Equation 2

Given: F = 1500 N, m = 600 kg

Substitute these values into equation 2

a = 1500/600

a = 2.5 m/s²

Hence the largest acceleration the rope can give to the car is 2.5 m/s²

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This equation goes with which law?
Alchen [17]

Answer:

I think that's Newton's second law of motion

Explanation:

f = m(v-u)

________

t

since a = (v-u)t

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3 0
3 years ago
an object has 5.00 kg*m/s of momentum. if you double the mass and double the velocity, how much momentum would it have PLEASE HE
KIM [24]

The final momentum is 20.00 kg*m/s

Explanation:

The momentum of an object is given by:

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For the object in the problem, the initial momentum is

p=mv=5.00 kg m/s

Then, the mass is doubled:

m' = 2m

And the velocity is also doubled:

v' = 2v

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Learn more about momentum:

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6 0
4 years ago
A spring of spring constant k=8.25N/m is displaced from equilibrium by a distance of 0.150m. What is the stored energy in the fo
inysia [295]

Answer:

0.0928J

Explanation:

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\int\limits^x_0 {-F} \, dx \\=\int\limits^x_0 {kx} \, dx \\\\=\frac{kx^{2} }{2}

*** Its fine if you know nothing about calculus. Just apply the equation

    U=\frac{kx^{2} }{2}

  where U is the potential energy of the spring***

  put x=0.150, U=\frac{8.25}{2}×0.150^{2} = 0.0928J (corr. to 3 sig. fig.)

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That is false I think sorry if its not correct
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Please i need the answer asap
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