Answer:
A. The force exerted by the sprinter must be 9.6 × 10² N.
B. The force that propels the sprinter is exerted by the blocks.
Explanation:
Hi there!
Let´s begin with part B:
The sprinter exerts a force on the blocks and, as a reaction, the blocks exert a force on the sprinter that is of equal magnitude but opposite direction (Newton´s third law). This reaction of the blocks causes the acceleration of the sprinter.
Part A
The force exerted by the blocks can be calculated using Newton´s second law:
F = m · a
Where:
F = exerted force.
m = mass of the object being accelerated.
a = acceleration of the object after applying the force on the object.
F = m · a
F = 64 kg · 15 m/s²
F = 9.6 × 10² N
For each route from Boston to Detroit, there are 6 possible routes to Los Angeles.
Therefore if there are 4 routes from Boston to Detroit, the number of routes from Boston to Los Angeles is
4*6 = 24
The diagram shown below illustrates the possible routes.
Answer: 24
Answer:
Explanation:
1 ) Magnetic field due to a circular coil carrying current
= μ₀I / 2r
I is current , r is radius of the wire , μ₀ = 4π x 10⁻⁷
= 4π x 10⁻⁷ x 15 / (2 x 3.5 x 10⁻²)
= 26.9 x 10⁻⁵ T
2 )
Negative z direction .
The direction of magnetic field due to a circular coil having current is known
with the help of screw rule or right hand thumb rule.
3 )
If we decrease the radius the magnetic field will:__increase _____.
A. Increase.
Magnetic field due to a circular coil carrying current
B = μ₀I / 2 r
Here r is radius of the coil . If radius decreases magnetic field increases.
So magnetic field will increase.
Answer:

Explanation:
Let the mass of copper ball is "m" gram
now the total number of copper atom present in the ball is given as

now the total number of electrons in one copper atom is 29
so total number of electrons in given sample of copper ball is

now diameter of the ball is 7.0 mm
density of the ball = 
now we have



now we have

now the charge on the copper ball is 40 nC
so the number of electrons removed



so the fraction of number of electrons removed is given as


