If a gas has a volume of 1.25 L and a pressure of 1.75 atm, what will the pressure be if the volume is changed to 3.15 L?
1 answer:
Assuming the temperature is kept constant during this change, you can use Boyle's Law to answer the question. The law relates the products of volume (V) and pressure (P) before and after:
Given V1, P1, and V2:
So, the pressure after the volume change, while the temperature is constant, will be 0.69 atmospheres. This is intuitive: the volume has increased with same amount of ideal gas, and so the pressure went down.
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Answer:
4 m/
Explanation:
From Equilibrium of forces, The Tension in string is cancelled by the Weight (product of mass and acceleration due to gravity) of the body acting downwards.
The Net force = Mass * Acceleration.
Since Net Force = 20 Newton, Mass = 5kg, therefore;
20 = 5kg * acceleration. Dividing the RHS and LHS of the equation by 5, we have;
Acceleration = which gives 4.
Note: RHS means Right Hand Side.
LHS means Left Hand Side.
Initially, the velocity vector is . At the same height, the x-value of the vector will be the same, and the y-value will be opposite (assuming no air resistance). Assuming perfect reflection off the ground, the velocity vector is the same. After 0.2 seconds at 9.8 seconds, the y-value has decreased by
, so the velocity is
.
Converting back to direction and magnitude, we get