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Nezavi [6.7K]
3 years ago
12

(Fill In The Blanks Plz)

Physics
1 answer:
Mice21 [21]3 years ago
8 0

Answer:

No. of Molecules = 18.06 x 10²³ molecules

No. of Atoms of P = 3 atoms

No. of Atoms of Na = 9 atoms

Total No. of Atoms = 24 atoms

Explanation:

<u>FOR NUMBER OF MOLECULES</u>:

No.\ of\ Molecules = (No.\ of\ Moles)(Avigadro's\ Number)\\No.\ of\ Molecules = (3)(6.02\ x\ 10^{23}\ molecules})\\

<u>No. of Molecules = 18.06 x 10²³ molecules</u>

<u></u>

<u>FOR NUMBER OF P ATOMS</u>:

No.\ of\ Atoms\ of\ P = (No.\ of\ Moles)(N.\ of atoms of P)\\No.\ of\ Atoms\ of\ P = (3)(1\ atom})

<u>No. of Atoms of P = 3 atoms</u>

<u></u>

<u>FOR NUMBER OF Na ATOMS</u>:

No.\ of\ Atoms\ of\ Na = (No.\ of\ Moles)(N.\ of atoms of Na)\\No.\ of\ Atoms\ of\ Na = (3)(3\ atom})

<u>No. of Atoms of Na = 9 atoms</u>

<u></u>

<u>FOR TOTAL NUMBER OF ATOMS</u>:

Total\ No.\ of\ Atoms = (No.\ of\ Moles)(N.\ of\ atoms\ of\ Na + No.\ of\ atoms\ of\ P + No.\ of\ atoms\ of\ O)\\ Total\ No.\ of\ Atoms\ = (3)(3\ atoms + 1\ atom + 4\ atoms}) = (3)(8\ atoms)

<u>Total No. of Atoms = 24 atoms</u>

<u></u>

<u></u>

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Answer:

The source is at a distance of 4.56 m from the first point.

Solution:

As per the question:

Separation distance between the points, d = 11.0 m

Sound level at the first point, L = 66.40 dB

Sound level at the second point, L'= 55.74 dB

Now,

L = 10log_{10}\frac{I}{I_{o}}          

I = I_{o}10^{\frac{L}{10}} = I_{o}10^{0.1L} = 10^{- 12}\times 10^{0.1\times 66.40} = 10^{- 5.36}      

L' = 10log_{10}\frac{I'}{I_{o}}

I' = I_{o}10^{\frac{L'}{10}} = 10^{- 12}\times 10^{0.1\times 55.74} = 10^{- 6.426}        

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I_{o} = 10^{- 12} W/m^{2}

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Now,

I = \frac{P}{4\pi R^{2}}

Similarly,

I' = \frac{P}{4\pi (R + 11.0)^{2}}

Now,

\frac{I}{I'} = \frac{(R + 11.0)^{2}}{R^{2}}

\frac{10^{- 5.36}}{10^{- 6.426}} = \frac{(R + 11.0)^{2}}{R^{2}}

R ^{2} + 22R + 121 = 11.64R^{2}}

10.64R ^{2} - 22R - 121 = 0

Solving the above quadratic eqn, we get:

R = 4.56 m

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A rock is dropped off a cliff and falls the first half of the distance to the ground in t1 seconds. If it falls the second half
Hitman42 [59]

Answer:

t2/t1 = \sqrt{2} - 1

Explanation:

The expression for the second law of motion is given below:

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Similarly,

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Using equation 2 by equation 1

we obtain 2 = (t1 + t2)^2/t1^2

Hence t2/t1 + 1 = \sqrt{2}

Hence t2/t1 = \sqrt{2} - 1

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Nezavi [6.7K]

Answer:

the velocity of the water flow is 7.92 m/s

Explanation:

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