All categories

4 years ago

I suck at finding area of circles plz help!!!

Mathematics

2 answers:

arlik [135]4 years ago

8 0

Area of circle = <span>π r^2
Given d = 22 in
radius r = d/2 = 22/2 = 11 in
So
A = </span><span>π r^2
A = 3.14 x (11)^2
A = 3.14 x 121
A = 379.94 in^2

Answer
A. </span>379.94 in^2

hodyreva [135]4 years ago

7 0

I believe it would be A

You might be interested in

What would be another way to write -8n-7

AysviL [449]

Answer:

-7 - 8n

Step-by-step explanation:

Another way would be to rearrange the terms = -7 - 8n

6 0

3 years ago

Find the volume of the rectangular pyramid below.

VMariaS [17]

Answer:

315 yd cubed

Step-by-step explanation:

To find the volume of the pyramid, we first need to consult the equation below. Thebase is for the rectangular portion, then after multiplied by the height it is divided by 3 to get the pyramid.

$\frac{1}{3} (B * H )$

To get the base, we multiply the length by the width.

21 * 9 = 189

189 * 5 = 945

945 divided by 3 = 315

5 0

3 years ago

Read 2 more answers

If the circle has the same diameter as the edge length of the square, then the area of this circle is ___________the area of the

WINSTONCH [101]

Answer:

The area of this circle is $(\frac{\pi}{2} )$ the area of the square.

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

Step-by-step explanation:

Area of the circle is given by;

$A_c = \frac{\pi d^2}{4}$

Area of the square is given by;

$A_s = L^2$

relationship between the edge length of the square, d, and length of its side, L,

$d = \sqrt{L^2 + L^2} \\\\d = \sqrt{2L^2}$

But area of the square , $A_s = L^2$

$d = \sqrt{2A_s}$

Then, the area of the square in terms of the edge length is given by;

$A_s = \frac{d^2}{2}$

Area of the circle in terms of area of the square is given by;

$A_c = \frac{\pi d^2}{4} = \frac{\pi}{2}(\frac{d^2}{2} )\\\\But \ A_s = \frac{d^2}{2} \\\\A_c = \frac{\pi}{2}(\frac{d^2}{2} )\\\\A_c = \frac{\pi}{2}(A_s )$

For the uniform electric field normal to the surface, the flux through the surface is electric field multiplied by the area of this surface.

Ф = E.A

Flux through the surface of the circle is given by;

$\phi _{circle} = E.(\frac{\pi d^2}{4})$

Flux through the surface of the square is given by;

$\phi _{square} = E.(\frac{d^2}{2} )\\\\\phi _{square} =E.(\frac{d^2}{2} ).(\frac{\pi}{2} ).(\frac{2}{\pi} )\\\\\phi _{square} =E.(\frac{\pi d^2}{4} ).(\frac{2}{\pi} )\\\\\phi _{square} =(\phi _{circle}).(\frac{2}{\pi} )$

Therefore, Φsquare is $(\frac{2}{\pi} )$ ϕcircle

5 0

3 years ago

How much do you need to divide to get 56

cluponka [151]

Answer:

560/10 WILL EQUAL TO 56

Step-by-step explanation:

7 0

4 years ago

The diameter of the cylinder is 6 cm.

iris [78.8K]

Answer:

254.34 cubed centimeters

Step-by-step explanation:

8 0

4 years ago