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Mazyrski [523]
3 years ago
6

how can you write

c{1}{\sqrt[3]{-12} }" alt="\frac{1}{\sqrt[3]{-12} }" align="absmiddle" class="latex-formula"> in a^{b} format without any radicals?
Mathematics
1 answer:
Andru [333]3 years ago
3 0

Answer:

\displaystyle (-12)^{-\frac{1}{3}}

General Formulas and Concepts:

<u>Algebra I</u>

  • Exponential Rule [Rewrite]:                                                                                 \displaystyle b^{-m} = \frac{1}{b^m}
  • Exponential Rule [Root Rewrite]:                                                                        \displaystyle \sqrt[n]{x} = x^{\frac{1}{n}}

Step-by-step explanation:

<u>Step 1: Define</u>

<u />\displaystyle \frac{1}{\sqrt[3]{-12}}<u />

<u />

<u>Step 2: Rewrite</u>

  1. Exponential Rule - Root Rewrite:                                                                    \displaystyle \frac{1}{(-12)^{\frac{1}{3}}}
  2. Exponential Rule - Rewrite:                                                                              \displaystyle (-12)^{-\frac{1}{3}}
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