I believe what you are wanting is f(x)= x+5.
Expand it
-(x+3)^2-1
-(x+3)(x+3)-1
-1(x^2+3x+3x+9)-1
-1(x^2+6x+9)-1
-x^2-9x-9-1
-x^2-9x-10
f(x)=-x^2-9x-10
Answer:
4 × (3 + 7) = (4 ×7) + (4 × 3)
Step-by-step explanation:
If you go by the order of PEMDAS you would do the parentheses first. 3 + 7 =10. 10 × 4 = 40. Then you would just use the distributive property and do (4× 7) + (4 × 3)
4 × 7 = 28 and 4 × 3 = 12 28 +12 =40
Answer:
x ≤ 3
General Formulas and Concepts:
<u>Pre-Algebra</u>
Order of Operations: BPEMDAS
- Brackets
- Parenthesis
- Exponents
- Multiplication
- Division
- Addition
- Subtraction
Distributive Property
Equality Properties
- Multiplication Property of Equality
- Division Property of Equality
- Addition Property of Equality
- Subtraction Property of Equality<u>
</u>
<u>Algebra I</u>
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>
2(4 + 2x) ≥ 5x + 5
<u>Step 2: Solve for </u><em><u>x</u></em>
- [Distributive Property] Distribute 2: 8 + 4x ≥ 5x + 5
- [Subtraction Property of Equality] Subtract 5x on both sides: 8 - x ≥ 5
- [Subtraction Property of Equality] Subtract 8 on both sides: -x ≥ -3
- [Division Property of Equality] Divide -1 on both sides: x ≤ 3