Answer:
<u>Part A: </u>
<u>n = 5q (1st equation)</u>
<u>0.05n + 0.25q = 2 (2nd equation)</u>
<u>Part B:</u>
<u>q = 4 ⇒ n = 5 * 4 = 20</u>
<u>Part C:</u>
<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>
Step-by-step explanation:
Let's recall that a nickel has a value of $ 0.05 and a quarter a value of $ 0.25.
Let n represent the number of nickels and q represent the number of quarters.
Part A:
Write a system of equations to represent the situation.
n = 5q (1st equation)
n * 0.05 + q * 0.25 = 2
0.05n + 0.25q = 2 (2nd equation)
Part B:
Replacing n in the 2nd equation to solve for q:
0.05n + 0.25q = 2
0.05 * 5q + 0.25q = 2
0.25q + 0.25q = 2
0.5q = 2
q = 2/0.5
<u>q = 4 ⇒ n = 5 * 4 = 20</u>
<u>Part C:</u>
<u>Margie has 20 nickels and 4 quarters, for a total of $ 2.00</u>
The example of exponential growth is: <span>c. y=0.5(1.5)x </span>
The function y = ab˟ is a can only be growth function if the value b>1. And if 0<b<1 it will decay. Therefore, the only correct value that fits the definition of exponential growth is option C.
Answer:
a) $520
b) $580
c) Interest amount is same each year
Step-by-step explanation:
Given - Georgie put $500 in her savings account, earning interest at a rate of 4% each year. She did not make any more deposits or withdrawals.
To find - a) How much money was in the account after one year?
b) How much money was in the account after 4 years?
c) Was the amount of money earned in interest the same or different each year?
Proof -
Here given that,
Principal amount = $500
rate of interest = 4% = 4/100 = 0.04
Now,
a)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(1)]
= 500 [ 1 + 0.04] = 520
⇒Amount = $520
b)
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(4)]
= 500 [ 1 + 0.16] = 580
⇒Amount = $580
c)
In 2nd year,
Amount = P [ 1 + RT ]
= 500 [ 1 + 0.04(2)]
= 500 [ 1 + 0.08] = 540
⇒Amount = $540
Now,
Interest in 1st year = 520 - 500 = 20
Interest in 2nd year = 540 - 520 = 20
So,
The interest amount is same each year
Answer: if i did my math correctly, 72 degrees is ur answer.
Step-by-step explanation: