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1 year ago

What is the probability of rolling a 1 on a number cube And then a 4?

Mathematics

1 answer:

mr Goodwill [35]1 year ago

5 0

For each number,there is a 16 probability of rolling it (so 16 for the 1 and also 16 for the 4)

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What is the value of x and the length of segment DE?

Mandarinka [93]

Answer:

Part 1) $x=6.6\ units$

Part 2) $DE=16.2\ units$

Step-by-step explanation:

Part 1) Find the value of x

we know that

Triangles CDF and FDE are similar

therefore

The ratio of its corresponding sides is proportional and its corresponding angles are congruent

$CD/FD=FD/DE$

$\frac{5}{9}=\frac{9}{2x+3} \\ \\5*(2x+3)=9*9\\ \\10x+15=81\\ \\10x= 81-15\\ \\10x=66\\ \\ x=6.6\ units$

Part 2) Find the length of DE

$DE=2x+3$

substitute the value of x

$DE=2(6.6)+3=16.2\ units$

8 0

2 years ago

Read 2 more answers

Plot the points A(7,1), B(-2, 3), C(1, -7) on the coordinate axes below. State the

Tanzania [10]

A B

D C

vectors

AB = DC

AB (-2-7 ; 3-1) => AB (-9 ; 2)

DC (1-x : -7-y)

1 - x = -9 => x = 10

-7-y = 2 => y = -9

D(10 ; -9)

4 0

2 years ago

CALCULUS: For an object whose velocity in ft/sec is given by v(t) = sin(t), what is its distance, in feet, travelled on the inte

rodikova [14]

The linked answer is wrong because that integral gives you the net displacement of the object, not the total distance.

To get the distance, you have to integrate the speed (as opposed to velocity), which involves integrating the absolute value of the velocity function.

$\mathrm{distance} = \displaystyle\int_1^5 |\sin(t)| \,\mathrm dt$

By definition of absolute value,

$|\sin(t)|=\begin{cases}\sin(t)&\text{for }\sin(t)\ge0\\-\sin(t)&\text{for }\sin(t)$

Over this particular integration interval,

• sin(t ) ≥ 0 for 1 ≤ t < π, and

• sin(t ) < 0 for π < t ≤ 5

so you end up splitting the integral at t = π as

$\mathrm{distance} = \displaystyle\int_1^\pi \sin(t)\,\mathrm dt + \int_\pi^5 (-\sin(t))\,\mathrm dt$

Now compute the distance:

$\mathrm{distance} = -\cos(t)\bigg|_1^\pi + \cos(t)\bigg|_\pi^5$

$\mathrm{distance} = -(\cos(\pi) - \cos(1)) + (\cos(5) - \cos(\pi))$

$\mathrm{distance} = -2\cos(\pi) + \cos(1) + \cos(5) \approx 2.82$

making B the correct answer.

7 0

2 years ago

If anyone could help?

Trava [24]

Answer:

$y=\frac{5}{7}x$ and $y=\frac{7}{9}x$

Step-by-step explanation:

A simple way to solve this problem is to plug the corresponding x and y into the function. We need only one pair since all the functions are quasi-linear (y=kx) and the increase is proportional.

In $y=\frac{5}{7}x$ when x=3, y=15/4≈2.14

In $y=\frac{3}{5}x$ when x=3, y=1.8