All categories

3 years ago

What is the answer to the math problem 5+9(2+4)?

2 answers:

eduard3 years ago

8 0

Answer:it's 22 because the perenthasies mean do it first and that is 4+2 which equals 6 then do 9+5 which is 16 then 16+6 equals 22.

Step-by-step explanation:

IceJOKER [234]3 years ago

6 0

Answer:

Step-by-step explanation:

Simplify the following:

5 + 9 (2 + 4)

2 + 4 = 6:

5 + 9×6

9×6 = 54:

5 + 54

5 + 54 = 59:

Answer: 59

You might be interested in

What Is the answer to 10ac-x/11=-3

cestrela7 [59]

Multiplty both sides by 11. 11 times 11 cancels out, 11 times -3 equals -33. You should get 10ac - x = -33
Add x to both sides: 10 a c = x − 33
Divide both sides by 10 c : a = x − 33 /10c

revised tada!

4 0

4 years ago

Mrs. Baca uses a phone card to call her relatives in Columbia. It costs her 45 cents to talk for 15 minutes. How long can she ta

aniked [119]

Answer:

25 minutes.

Step-by-step explanation:

Unit rate = 45/15 = 3 cents / minute.

So she pays 3 cents for 1 minute

and for 75 cents she can talk for 75 * 1/3 = 25 minutes.

7 0

3 years ago

Can anyone do question 25 part c? :)

inna [77]

$\begin{cases}x^3\qquad\qquad\ \ \ when\ x\geq3\\5\qquad\qquad\quad \ when\ 0\ \textless \ x\ \textless \ 3\\x^2-x+2\quad\ when\ x\leq0 \end{cases}\\\\\\ (a)\\ f(0)\iff x=0\implies f(x)=x^2-x+2\\\\f(0)=0^2-0+2=2\\\\(b)\\ \{f(2)\iff x=2;\ \ f(1)\iff x=1\}\implies f(x)=5\\\\ f(2)=5\quad\wedge\quad f(1)=5\\\\ f(2)-f(1)=5-5=0$

$(c)\\ \big\forall \limits_{ n\in R}\ n^2\geq 0\ \ \Rightarrow\ \ \big\forall \limits_{ n\in R}\ (-n^2)\leq 0 \ \ \Rightarrow\ \ x\leq0\ \ \Rightarrow\ \ f(x)=x^2-x+2\\\\f(-n^2)=(-n^2)^2-(-n^2)+2=n^4+n^2+2$

5 0

3 years ago

Find three consecutive odd integers such that the sum of the smallest number and twice the largest number is equal to fifteen mo

inn [45]

Answer:

The three consecutive odd integers are: -11, -13 and -15.

Step-by-step explanation:

Let the smallest number be represented by x. then the three consecutive odd integers are: x, (x + 2) and (x = 4).

The sum of the smallest number and twice the larges number = x + 2(x + 4)

Fifteen more than four times the middle number = 4(x + 2) + 15

So that;

x + 2(x + 4) = 4(x + 2) + 15

x + 2x + 8 = 4x + 8 + 15

3x + 8 = 4x + 23

3x - 4x = 23 - 8

-1x = 15

⇒ x = -15

(x + 2) = (-15 + 2) = -13

(x + 4) = (-15 + 4) = -11

The three consecutive odd integers are: -11, -13 and -15.

7 0

4 years ago

The graph of the function f(x)=x^2-6x shifted 2 units to the left on the graph of g(x). Select the two functions that represent

Nimfa-mama [501]

The correct answer is

g(x) =f(x+2)
And

g(x)=x^2-2x-8

8 0

3 years ago