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taurus [48]
2 years ago
13

What is the answer to the math problem 5+9(2+4)?

Mathematics
2 answers:
eduard2 years ago
8 0

Answer:it's 22 because the perenthasies mean do it first and that is 4+2 which equals 6 then do 9+5 which is 16 then 16+6 equals 22.

Step-by-step explanation:

IceJOKER [234]2 years ago
6 0

Answer:

59

Step-by-step explanation:

Simplify the following:

5 + 9 (2 + 4)

2 + 4 = 6:

5 + 9×6

9×6 = 54:

5 + 54

5 + 54 = 59:

Answer:  59

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Using the scale of 5 cm: 25 m, find the actual length of the parking lot. Be sure to include units.
k0ka [10]

Answer:

25 m = 25 × 100 = 2500 cm

5 ÷ 5 = 1

2500 ÷ 5 = 500

5:2500 ratio simplified is 1:500

Step-by-step explanation:

5 0
2 years ago
Read 2 more answers
Can you please help me out
Taya2010 [7]

The bag contains,

Red (R) marbles is 9, Green (G) marbles is 7 and Blue (B) marbles is 4,

Total marbles (possible outcome) is,

\text{Total marbles = (R) + (G) +(B) = 9 + 7 + 4 = 20 marbles}

Let P(R) represent the probablity of picking a red marble,

P(G) represent the probability of picking a green marble and,

P(B) represent the probability of picking a blue marble.

Probability , P, is,

\text{Prob, P =}\frac{required\text{ outcome}}{possible\text{ outcome}}\begin{gathered} P(R)=\frac{9}{20} \\ P(G)=\frac{7}{20} \\ P(B)=\frac{4}{20} \end{gathered}

Probablity of drawing a Red marble (R) and then a blue marble (B) without being replaced,

That means once a marble is drawn, the total marbles (possible outcome) reduces as well,

\begin{gathered} \text{Prob of a red marble P(R) =}\frac{9}{20} \\ \text{Prob of }a\text{ blue marble =}\frac{4}{19} \\ \text{After a marble is selected without replacement, marbles left is 19} \\ \text{Prob of red marble + prob of blue marble = P(R) + P(B) = }\frac{9}{20}+\frac{4}{19}=\frac{251}{380} \\ \text{Hence, the probability is }\frac{251}{380} \end{gathered}

Hence, the best option is G.

5 0
1 year ago
What is the percentage:<br><br> 16 out of 20
gtnhenbr [62]
16/20= .80
.80 x 100%
=80%
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Vaselesa [24]
I say that x equals 5
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