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iVinArrow [24]
3 years ago
10

A rectangular carpet measures 12 m by 5 m.

Mathematics
1 answer:
Zepler [3.9K]3 years ago
8 0

Answer:

\frac{1}{15}

Step-by-step explanation:

Area of the Rectangular Carpet=12*5=60m²

Area of the Square rug=2*2=4m²

Expressing the area of the rug as a fraction of the total area of the carpet, we have:

\frac{\text{Area of Rug}}{\text{Area of Carpet}}=\frac{4}{60}\\=\frac{1}{15}.

The fraction of the carpet that is covered by the rug is \frac{1}{15}.

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What’s 4%x56? 2 A.2.24 B.1.12 or C.0.448
MissTica

Answer:

A. 2.24

Step-by-step explanation:

Multiply 56 by 0.04

56(0.04)

= 2.24

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The net of a rectangular prism is shown below. What is the total surface area of the rectangular prism represented by this net?
Finger [1]

Answer:

150.88 cm²

Step-by-step explanation:

A rectangular prism also known as cuboid is a three dimensional object with six rectangular faces and eight vertices. It is a prism because it has the same cross section along the length. It is called a rectangular prism because its cross section is rectangular.

The opposite faces of a rectangular prism are equal to each other.

The total surface area (TSA) of a rectangular prism is:

TSA = 2(wl + wh + lh)

where w is the width of the base, l is the length of the base and h is the height of the prism.

From the question, we can see that:

w = 5 cm, l = 7.4 cm and h = 3.1 cm. therefore:

TSA = 2(wl + wh + lh) = 2[(5 * 7.4) + (5 * 3.1) + (7.4 * 3.1)] = 2(37 + 15.5 + 22.94)

TSA = 2(75.44)

TSA = 150.88 cm²

3 0
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38 years ago George was 14, how old is he now
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Evaluate the six trigonometric functions of the angle 0<br><br><br><br>is right<br>​
antiseptic1488 [7]

Answer:

1. Sine θ = 1/3

2. Cos θ = 2√2 / 3

3. Tan θ = √2 / 4

4. Cosec θ = 3

5. Sec θ = 3√2 / 4

6. Cot θ = 2√2

Step-by-step explanation:

We'll begin by determining the adjacent. This can be obtained as follow:

Hypothenus (Hypo) = 9

Opposite (Opp) = 3

Adjacent (Adj) =?

Hypo² = Adj² + Opp²

9² = Adj² + 3²

81 = Adj² + 9

81 – 9 = Adj²

72 = Adj²

Take the square root of both side

Adj = √72

Adj = 6√2

Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:

1. Determination of Sine θ

Hypothenus = 9

Opposite = 3

Sine θ =?

Sine θ = Opposite / Hypothenus

Sine θ = 3/9

Sine θ = 1/3

2. Determination of Cos θ

Adjacent = 6√2

Hypothenus = 9

Cos θ =?

Cos θ = Adjacent / Hypothenus

Cos θ = 6√2 / 9

Cos θ = 2√2 / 3

3. Determination of Tan θ

Opposite = 3

Adjacent = 6√2

Tan θ =?

Tan θ = Opposite / Adjacent

Tan θ = 3 / 6√2

Tan θ = 1 / 2√2

Rationalise

(1 / 2√2) × (2√2 /2√2)

= 2√2 / 4×2

Tan θ = √2 / 4

4. Determination of Cosec θ

Sine θ = 1/3

Cosec θ =?

Cosec θ = 1 / Sine θ

Cosec θ = 1 ÷ 1/3

Cosec θ = 1 × 3/1

Cosec θ = 3

5. Determination of sec θ

Cos θ = 2√2 / 3

Sec θ =?

Sec θ = 1 / Cos θ

Sec θ = 1 ÷ 2√2 / 3

Sec θ = 1 × 3 / 2√2

Sec θ = 3 / 2√2

Rationalise

= (3 / 2√2) × (2√2 / 2√2)

= 3 × 2√2 / 4×2

Sec θ = 3√2 / 4

6. Determination of Cot θ

Tan θ = √2 / 4

Cot θ =?

Cot θ = 1 / Tan θ

Cot θ = 1 ÷ √2 / 4

Cot θ = 1 × 4 / √2

Cot θ = 4 / √2

Rationalise

= (4 / √2) × (√2 / √2)

= 4√2 / 2

Cot θ = 2√2

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Step-by-step explanation:

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