Answer:
A. 2.24
Step-by-step explanation:
Multiply 56 by 0.04
56(0.04)
= 2.24
Answer:
150.88 cm²
Step-by-step explanation:
A rectangular prism also known as cuboid is a three dimensional object with six rectangular faces and eight vertices. It is a prism because it has the same cross section along the length. It is called a rectangular prism because its cross section is rectangular.
The opposite faces of a rectangular prism are equal to each other.
The total surface area (TSA) of a rectangular prism is:
TSA = 2(wl + wh + lh)
where w is the width of the base, l is the length of the base and h is the height of the prism.
From the question, we can see that:
w = 5 cm, l = 7.4 cm and h = 3.1 cm. therefore:
TSA = 2(wl + wh + lh) = 2[(5 * 7.4) + (5 * 3.1) + (7.4 * 3.1)] = 2(37 + 15.5 + 22.94)
TSA = 2(75.44)
TSA = 150.88 cm²
You need to add 38 and 14 together to get answer of 52 years old.
Answer:
1. Sine θ = 1/3
2. Cos θ = 2√2 / 3
3. Tan θ = √2 / 4
4. Cosec θ = 3
5. Sec θ = 3√2 / 4
6. Cot θ = 2√2
Step-by-step explanation:
We'll begin by determining the adjacent. This can be obtained as follow:
Hypothenus (Hypo) = 9
Opposite (Opp) = 3
Adjacent (Adj) =?
Hypo² = Adj² + Opp²
9² = Adj² + 3²
81 = Adj² + 9
81 – 9 = Adj²
72 = Adj²
Take the square root of both side
Adj = √72
Adj = 6√2
Finally, we shall determine six trigonometric functions of the angle θ. This Can be obtained as follow:
1. Determination of Sine θ
Hypothenus = 9
Opposite = 3
Sine θ =?
Sine θ = Opposite / Hypothenus
Sine θ = 3/9
Sine θ = 1/3
2. Determination of Cos θ
Adjacent = 6√2
Hypothenus = 9
Cos θ =?
Cos θ = Adjacent / Hypothenus
Cos θ = 6√2 / 9
Cos θ = 2√2 / 3
3. Determination of Tan θ
Opposite = 3
Adjacent = 6√2
Tan θ =?
Tan θ = Opposite / Adjacent
Tan θ = 3 / 6√2
Tan θ = 1 / 2√2
Rationalise
(1 / 2√2) × (2√2 /2√2)
= 2√2 / 4×2
Tan θ = √2 / 4
4. Determination of Cosec θ
Sine θ = 1/3
Cosec θ =?
Cosec θ = 1 / Sine θ
Cosec θ = 1 ÷ 1/3
Cosec θ = 1 × 3/1
Cosec θ = 3
5. Determination of sec θ
Cos θ = 2√2 / 3
Sec θ =?
Sec θ = 1 / Cos θ
Sec θ = 1 ÷ 2√2 / 3
Sec θ = 1 × 3 / 2√2
Sec θ = 3 / 2√2
Rationalise
= (3 / 2√2) × (2√2 / 2√2)
= 3 × 2√2 / 4×2
Sec θ = 3√2 / 4
6. Determination of Cot θ
Tan θ = √2 / 4
Cot θ =?
Cot θ = 1 / Tan θ
Cot θ = 1 ÷ √2 / 4
Cot θ = 1 × 4 / √2
Cot θ = 4 / √2
Rationalise
= (4 / √2) × (√2 / √2)
= 4√2 / 2
Cot θ = 2√2
