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soldi70 [24.7K]
3 years ago
14

Sin a + cos a/sec a+ cosec a= sin a* cos a

Mathematics
1 answer:
FrozenT [24]3 years ago
4 0

Answer:

See proof below

Step-by-step explanation:

sin a + cos a/sec a+ cosec a= sin a* cos a

(sina+cosa)/(sec a + cosec a)

In trigonometry identity

seca = 1/cos a

cosec a = 1/sin a

Substituted into the given expression

= sina + cosa/(1/cosa+1/sina)

Find the LCM

= sina + cosa /(sina+cosa/sinacosa)

= (sina+cosa) * sinacosa/(sina + cosa)

= sinacosa (RHS)

This shows that the equation is true

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Hello from MrBillDoesMath!

Answer:

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Discussion:

(4x +5) ( 2x - 2) =  8x^2 - 8x + 10x - 10        

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