The total number of packages completed was 41 and with 60 moustraps per package so 41 x 60 = 2460. Of these, 52 traps were from the previous shift and 34 were rejects so 2460-52-34 = 2374 produced + 24 in the last unsealed package = 2374 +24 = 2398.
Answer:
(8, 4)
Step-by-step explanation:
<em>AD is enlarged to JM</em>
<em>AD² = 2² + 1² = 4 + 1 =5</em>
<em>AD = √5</em>
then you plug in JM
<em>JM² = 6² + 3² = 36 + 9 = 45</em>
<em>JM = √45 = 3 √5</em>
<em>so if </em>
<em>JM=3 AD</em>
then
<em>ML= 3 DC </em>
<em>then you add</em>
<em>5+3=8</em>
the coordinates for point L are (8, 4)
Well the are six sides and numbers on the dices and two sides on the coin so there would be 8 outcomes
C because you have to think a bout how to get from y to x
Interpreting the situation, it is found that Marjorie will have 240 left after paying her penalty.
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- When the piece lands on the red square, the penalty is equal to <u>30 times the sum they roll on two numbers.</u>
- Marjorie rolls 4 and 2, thus, the sum is 6.
- The penalty is of

- She currently has 420, the penalty removes 180, thus, she will have 420 - 180 = 240 left after paying her penalty.
A similar problem is given at brainly.com/question/12166019