10. Name the property illustrated in this statement. If a = 6+3 and 6+3 = 9, then a = 9.

A cube-shaped box can be wrapped completely in gift wrap that measures 384 square inches. What is the volume of the box?

aev [14]

Answer:

7529.536

Step-by-step explanation:

√384=19.6

19.6, is therefore the length of one side

Volume of cube is length³

19.6³=7529.536

Well it's just a try for me

5 0

3 years ago

I need help ? I can’t figure it out can someone help me plz

dalvyx [7]

The answer is C).

If each cost .19 and ounce you would use x to indicate the unknown value therefore you will have .19x. the x is the amount of ounces which is 8. So .19 x 8 which equals 1.52.

8 0

3 years ago

Solve the given equation 7ex – 9 = 10

maria [59]

Answer: x = 10.18

Step-by-step explanation:

7ex – 9 = 10

(x-9)*ln7 = ln 10

x-9 = 2.30/1.95

x = 10.18

3 0

3 years ago

If BOTH equations are in slope-intercept form then the--------------? method would be best, but the------------? method would al

nadezda [96]

Answer:

Step-by-step explanation:

If BOTH equations are in slope-intercept form then the-graphing-? method would be best, but the-substitution-? method would also be effective since both y's are already by itself.

If ONE of the equations is solved for x or y and the other equation is not, then the-substitution-? method is best.

If BOTH equations are lined up in standard form & the coefficients of x or y are opposites then the BEST method is definitely the-elimination--? method.

If BOTH equations are lined up in standard form the elimination method would be best. But if the coefficient of x or y is 1, then the-substitution--? method is also effective.

5 0

3 years ago

When circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%. Let

sergiy2304 [10]

Answer:

(a) P(X=3) = 0.093

(b) P(X≤3) = 0.966

(c) P(X≥4) = 0.034

(d) P(1≤X≤3) = 0.688

(e) The probability that none of the 25 boards is defective is 0.277.

(f) The expected value and standard deviation of X is 1.25 and 1.089 respectively.

Step-by-step explanation:

We are given that when circuit boards used in the manufacture of compact disc players are tested, the long-run percentage of defectives is 5%.

Let X = the number of defective boards in a random sample of size, n = 25

So, X ∼ Bin(25,0.05)

The probability distribution for the binomial distribution is given by;

$P(X=r)= \binom{n}{r} \times p^{r}\times (1-p)^{n-r} ; x = 0,1,2,......$

where, n = number of trials (samples) taken = 25

r = number of success

p = probability of success which in our question is percentage

of defectivs, i.e. 5%

(a) P(X = 3) = $\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $2300 \times 0.05^{3}\times 0.95^{22}$

= 0.093

(b) P(X $\leq$ 3) = P(X = 0) + P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{0} \times 0.05^{0}\times (1-0.05)^{25-0}+\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$

= $1 \times 1 \times 0.95^{25}+25 \times 0.05^{1}\times 0.95^{24}+300 \times 0.05^{2}\times 0.95^{23}+2300 \times 0.05^{3}\times 0.95^{22}$

= 0.966

(c) P(X $\geq$ 4) = 1 - P(X < 4) = 1 - P(X $\leq$ 3)

= 1 - 0.966

= 0.034

(d) P(1 ≤ X ≤ 3) = P(X = 1) + P(X = 2) + P(X = 3)

= $\binom{25}{1} \times 0.05^{1}\times (1-0.05)^{25-1}+\binom{25}{2} \times 0.05^{2}\times (1-0.05)^{25-2}+\binom{25}{3} \times 0.05^{3}\times (1-0.05)^{25-3}$