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3 years ago

Please help me answer this using systems of equations with elimination.

Mathematics

1 answer:

Triss [41]3 years ago

3 0

-5x+13y=-7
5x+4y=24
add the equation to eliminate x:
13y+4y=-7+24
17y=17
solve for y:
17/17y=17/17
y=1
then plug in y into any equation to solve for x:
-5x+13y=-7, y=1
-5x+(13*1)=-7
-5x+13-13=-7-13
-5x=-20
-5/-5x=-20/-5
x=4
the answers are x=4, y=1

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$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

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Step-by-step explanation:

Step(i):-

Given b = 3 and hypotenuse c = 5

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By using pythagoras theorem

c² = a² + b²

⇒ a² = c² - b²

⇒ a² = 5²-3²

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⇒ a = √16 = 4

The sides of right angle triangle a = 4 ,b = 3 and c = 5

Step(ii):-

$sin(A) = \frac{opposite side}{Hypotenuse} = \frac{a}{c} = \frac{4}{5}$

$cos(A) = \frac{Adjacent side}{Hypotenuse} = \frac{b}{c} = \frac{3}{5}$

$tan(A) = \frac{opposite side}{Adjacent side} = \frac{a}{b} = \frac{4}{3}$

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