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2 years ago

H

Mathematics

1 answer:

Dafna11 [192]2 years ago

4 0

y =mx+b

Im pretty sure that is correct

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What is the slope of the line passing through the points (−3, 4) and (2, −1)?

hram777 [196]

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3 years ago

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What is the estimate of 824 ÷ 42

Fiesta28 [93]

Answer:34.333 repeating

Step-by-step explanation:

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2 years ago

when coloring in a grid to show a fraction, what does 3/10 look like when the grid represents a whole

Katarina [22]

Answer:

3 of 10 grid squares making up the whole will be colored.

Step-by-step explanation:

1/10 is one of ten equal parts. 3/10 is three of those ten equal parts. Essentially, the fraction 3/10 means "three out of ten".

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If the whole is divided into more than 10 parts, 3/10 will be 3 out of every 10. So if there are 20 parts, for example (2 tens), the 3/10 will be 6 of those parts (3 of each of the two tens).

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2 years ago

Triangle EFG has vertices E(-3,1), F(1,1), and G(4,5). Find the coordinates of the image of point of E after a translation of 3

torisob [31]

Answer:

E(-1,3) F(3,-2) G(6,2)

Step-by-step explanation:

It's just simple addition and subtraction. The x-coordinate would add 2 since it is going to the right, which is positive. The y-coordinate would subtract 3 since going down be negative.

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2 years ago

One thousand tonnes (1000 t, one t equals 10 cubed kg) of sand contains about a trillion (10 super 12) grains of sand. How many

Phantasy [73]

Answer with Step-by-step explanation:

Since 1 mole of sand will contain Avagadro's Number of sand particles (by definition of 1 mole)

Thus we have

1 mole of sand = $6.022\times 10^{23}$ sand particles

Thus in number of trillion sand particles we have no of trillion sand particles in 12 mole is

$\frac{6.022\times 10^{23}}{10^{12}}=6.022\times 10^{11}$

Now since it is given that mass of 1 trillion sand particles is 1000 tonnes Thus the mass of $6.022\times 10^{11}$ trillion sand particles is

$Mass=1000\times 6.022\times 10^{11}=6.022\times 10^{14}tonnes$

Part 2)

Since it is given that volume of 1 sand particle is $1.0mm^{3}$ thus the volume of 1 mole of sand is volume of $6.022\times 10^{23}$ sand particles

Thus volume of 1 mole is $V=1.00\times 10^{-18}km^{3}\times 6.022\times 10^{23}=6.022\times 10^{5}km^{3}$

Now since the Area of united states is $A=3.6\times 10^{6}mile^{2}=5.8\times 10^{6}km^{2}$

Thus the depth of the sand pile is

$Depth=\frac{Volume}{Area}=\frac{6.022\times 10^5}{5.8\times 10^6}=0.10387km=103.8meters$

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2 years ago