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aleksley [76]
3 years ago
9

Which expression is equivalent to : (2n - 3)?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer: Choice C) \frac{8}{9}n - 1\frac{1}{3}

====================================================

Explanation:

We multiply the outer term 4/9 with each term inside

  • (4/9) times (2n) = (4*2n)/9 = (8n)/9 = (8/9)n
  • (4/9) times (-3) = (4*(-3))/9 = -12/9 = -4/3

The improper fraction 4/3 converts to the mixed number 1 & 1/3

4/3 = (3+1)/3 = 3/3 + 1/3 = 1 + 1/3 = 1 & 1/3

So overall, we can say \frac{4}{9}(2n-3) = \frac{8}{9}n - 1\frac{1}{3}

This is equivalent to saying \frac{4}{9}(2n-3) = \frac{8}{9}n - \frac{4}{3}

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1 year ago
Two equations are given below: a – 3b = 9 a = b – 3 What is the solution to the set of equations in the form (a, b)?
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A-3b=9
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Solution: (-9,-6)
----
Check: 
-9=-6-3
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TRUE


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2 years ago
The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second. Use the central limi
Mila [183]

Answer:

0.048 is the probability that more than 950 message arrive in one minute.

Step-by-step explanation:

We are given the following information in the question:

The number of messages arriving at a multiplexer is a Poisson random variable with mean 15 messages/second.

Let X be the number of messages arriving at a multiplexer.

Mean = 15

For poison distribution,

Mean = Variance = 15

\text{Standard Deviation} = \sqrt{\text{Variance}} = \sqrt{15} = 3.872

From central limit theorem, we have:

z = \displaystyle\frac{x-n\mu}{\sigma\sqrt{n}}

where n is the sample size.

Here, n = 1 minute = 60 seconds

P(x > 950)

P( x > 950) = P( z > \displaystyle\frac{950 - (60)(15)}{\sqrt{(15)(60)}}) = P(z > 1.667)

= 1 - P(z \leq 1.667)

Calculation the value from standard normal z table, we have,  

P(x > 950) = 1 - 0.952 = 0.048

0.048 is the probability that more than 950 message arrive in one minute.

3 0
3 years ago
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