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aleksley [76]
3 years ago
9

Which expression is equivalent to : (2n - 3)?

Mathematics
1 answer:
Zigmanuir [339]3 years ago
6 0

Answer: Choice C) \frac{8}{9}n - 1\frac{1}{3}

====================================================

Explanation:

We multiply the outer term 4/9 with each term inside

  • (4/9) times (2n) = (4*2n)/9 = (8n)/9 = (8/9)n
  • (4/9) times (-3) = (4*(-3))/9 = -12/9 = -4/3

The improper fraction 4/3 converts to the mixed number 1 & 1/3

4/3 = (3+1)/3 = 3/3 + 1/3 = 1 + 1/3 = 1 & 1/3

So overall, we can say \frac{4}{9}(2n-3) = \frac{8}{9}n - 1\frac{1}{3}

This is equivalent to saying \frac{4}{9}(2n-3) = \frac{8}{9}n - \frac{4}{3}

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40y^14/10y^8 simplify radicals and use properties of rational exponents
Vadim26 [7]

Answer:

4y^6

Step-by-step explanation:

Take out the constants:

40y^14/10y^8

= 40/10 * y^14 / y^8

= 4 * y^(14-8)

= 4 * y^6

= 4y^6

Hope this helped you :3

7 0
4 years ago
Find the measures of HAB and CAB.
Paha777 [63]

Answer: Angle HAB= 66 and Angle CAB= 44

Step-by-step explanation:

Since angle EAF=90 and FAD=20 then DAH must equal 70 degrees because it is 180 degree angle. Since DAH and EAC are vertical angles they are equal so EAC = DAH= 70 degrees. For the other side of 180 degrees then 70+5x=180

5x=110

x=22

CAB= 2(22)= 44 degrees

HAB= 3(22)=66 degrees

4 0
3 years ago
A fish tank has a base area of 45cm2 and is filled with water to a depth of 12cm.If the height of the tank is 25cm, how much wat
stepladder [879]

Answer:

Step-by-step explanation:

v = 45 * 12

v = 540cm³

To fill the tank,

v = 45 * 25

v = 1,125cm³

I'm not quite sure what the exact question is so i'll answer both;

1.) The volume of water required to fill the tank from empty = 1,125cm³

2.) The volume of water required to fill the tank from it's current level is

1,125cm³ - 540cm³ = 585cm³

6 0
3 years ago
Suppose that you had the following data set. 500 200 250 275 300 Suppose that the value 500 was a typo, and it was suppose to be
hodyreva [135]

Answer:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

Step-by-step explanation:

The subindex B is for the before case and the subindex A is for the after case

Before case (with 500)

For this case we have the following dataset:

500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_B = \frac{\sum_{i=1}^5 X_i}{5} =\frac{500+200+250+275+300}{5}=\frac{1525}{5}=305

And the sample deviation with the following formula:

s_B = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(500-305)^2 +(200-305)^2 +(250-305)^2 +(275-305)^2 +(300-305)^2)}{5-1}} = 115.108

After case (With -500 instead of 500)

For this case we have the following dataset:

-500 200 250 275 300

We can calculate the mean with the following formula:

\bar X_A = \frac{\sum_{i=1}^5 X_i}{5} =\frac{-500+200+250+275+300}{5}=\frac{525}{5}=105

And the sample deviation with the following formula:

s_A = \sqrt{\frac{\sum_{i=1}^5 (X_i-\bar X)^2}{n-1}}=\sqrt{\frac{(-500-105)^2 +(200-105)^2 +(250-105)^2 +(275-105)^2 +(300-105)^2)}{5-1}} = 340.221

And as we can see we have a significant change between the two values for the two cases.

The absolute difference is:

Abs = |340.221-115.108|= 225.113

If we find the % of change respect the before case we have this:

\% Change = \frac{|340.221-115.108|}{115.108} *100 = 195.57\%

So then is a big change.

8 0
4 years ago
I’ll give brainliest
diamong [38]

Answer:

A=115.6

Step-by-step explanation:

Hey There!

So the first step is to find the formula for area of a trapezoid

A = \frac{1}{2} h(b1 +b2)

h = height

b1 = base 1

b2 = base 2

now all we do its plug in the values

A=\frac{1}{2} 6.8(28.3+5.7)

6.8x26.3=192.44\\5.7x6.8=38.76\\38.76+192.44=231.2\\\frac{231.2}{2} =115.6\\A=115.6

Hope this helps!!

3 0
3 years ago
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