Answer:
y=2x+1
Step-by-step explanation:
First you have to find the slope:
5-1/2 so 4/2 or 2
Then you write it in point-slope: (I used the point (0,1))
y-1=2x
Simplify than:
y=2x+1
<span>It is clear to see that 0.0259 is less than 0.05. A p-value that is less than the confidence level of alpha indicates that there is sufficient evidence from the data that the null hypothesis should be rejected in favor of an alternative hypothesis.</span>
Answer:
![\displaystyle \frac{d}{dx}[3x + 5x] = 8](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%5B3x%20%2B%205x%5D%20%3D%208)
General Formulas and Concepts:
<u>Calculus</u>
Differentiation
- Derivatives
- Derivative Notation
Derivative Property [Multiplied Constant]: ![\displaystyle \frac{d}{dx} [cf(x)] = c \cdot f'(x)](https://tex.z-dn.net/?f=%5Cdisplaystyle%20%5Cfrac%7Bd%7D%7Bdx%7D%20%5Bcf%28x%29%5D%20%3D%20c%20%5Ccdot%20f%27%28x%29)
Basic Power Rule:
- f(x) = cxⁿ
- f’(x) = c·nxⁿ⁻¹
Step-by-step explanation:
<u>Step 1: Define</u>
<em>Identify</em>

<u>Step 2: Differentiate</u>
- Simplify:

- Derivative Property [Multiplied Constant]:
![\displaystyle y' = 8\frac{d}{dx}[x]](https://tex.z-dn.net/?f=%5Cdisplaystyle%20y%27%20%3D%208%5Cfrac%7Bd%7D%7Bdx%7D%5Bx%5D)
- Basic Power Rule:

Topic: AP Calculus AB/BC (Calculus I/I + II)
Unit: Differentiation
Answer:
See below
Step-by-step explanation:
Remember that quadratic functions are parabolas when graphed. The solutions are where the parabola crosses the x-axis.
1. The vertex of the parabola in f(x) is (0, 9) which is above the x-axis and the parabola opens up. So the parabola does not cross the x-axis. Therefore the solutions are imaginary.
2. The vertex of the parabola in g(x) is (9, 0) which is on the x-axis and parabola opens up. Therefore, there is a double solution.
3. The vertex of the parabola in h(x) is (-1, -9) which is below the x-axis and the parabola opens up. Therefore, there are two real solutions.
I know this is a long explanation, but that is a way of looking at the problem.