Answer:
1. 33%
2. 16%
3. 50%
Step-by-step explanation:
Answer:
I say A if you need anymore help just tell me!!!
Steps To Solve:
x² + 6 = 10
~Subtract 6 to both sides
x² + 6 - 6 = 10 - 6
~Simplify
x² = 4
~Take square root of 4
x² = ±√4
~Simplify
x = -2 or x = 2
Best of Luck!
Answer:
D.
Step-by-step explanation:
adding 8 cancels it out on side with x, the left side
The probability of the Bob arrived before 1.30 P.M is 1/2 if the Alice arrives after Bob.
According to the question,
Alice and Bob each arrive at a party at a random time between 1.00 P.M and 2.00 P.M.
In probability theory, the sample space(s) of a random trial is the set all possible results of that trial.
Let 'x' be the arrival time of Alice and 'y' be the arrival time of Bob.
s = {(x, y) /1≤x≤2 and 1≤y≤2}
In order to find the probability of the Bob arrived before 1.30 P.M, if the Alice arrives after Bob.
Formula for Probability =
= 1/2
Hence, the probability of the Bob arrived before 1.30 P.M is 1/2 if the Alice arrives after Bob.
Learn more about probability here
brainly.com/question/1979764
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