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mote1985 [20]
2 years ago
14

Help me please thank you

Mathematics
1 answer:
Lynna [10]2 years ago
5 0
Nice excellent wonderful
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Please show me step by step on how to solve this.
Readme [11.4K]
Well, you have to be given an interval. That is not an interval.

You should be given something like 1 \leq x \leq 2

If you add those fractions up you'll just get a point on the number line.

Find the LCD for all of them which is 9/6 - 4/6 + 3/6 = 8/6 = 2/3

You'll end up with a point on 2/3 
7 0
3 years ago
(2x-2) (x+5) what does x =
Lynna [10]

Answer:

a

x

2

+

b

x

+

c

=

0

the two roots of the equation take the form

x

1

,

2

=

−

b

±

√

b

2

−

4

a

c

2

a

So, start by adding

−

5

to both sides of the equation to get

2

x

2

+

x

−

5

=

5

−

5

2

x

2

+

x

−

5

=

0

Notice that you have

a

=

2

,

b

=

1

, and

c

=

−

5

. This means that the two solutions will be

x

1

,

2

=

−

1

±

√

1

2

−

4

⋅

2

⋅

(

−

5

)

2

⋅

2

x

1

,

2

=

−

1

±

√

41

4

You can simplify this if you want to get

x

1

=

−

1

+

√

41

4

≅

1.35078

and

x

2

=

−

1

−

√

41

4

≅

−

1.85078

4 0
2 years ago
Read 2 more answers
Suppose f(x)=x^2 what is the graph of g(x)= f(5x)
Novosadov [1.4K]

Answer:

Step-by-step explanation:

That '5' in f(5x) will compress the graph of x^2 horizontally.

If you were to graph f(x) = x^2, you'd get a parabolic graph; the parabola will open UP.

Suppose you graphed f(x) = x^2 on the interval [-4, 4].

Then the graph of g(x) = f(5x) would be graphed on the interval [-4/5, 4/5].  In other words, the graph would be on a shorter interval, one shorter by a factor of 5.

6 0
3 years ago
Read 2 more answers
How well can you apply Boyle’s law to this sample of gas that experiences changes in pressure and volume? Assume that temperatur
emmasim [6.3K]

Answer:

A = 1.0 L

B = 0.50 atm

C = 0.60 atm

D = 4.0 L

Step-by-step explanation:

According to the Boyle's law, the volume of a gas is inversely proportional to its volume. If we consider an initial state (1) and a final state (2):

P₁ × V₁ = P₂ × V₂

A

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = 3.0 atm × A

A = 1.0 L

B

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = B × 6.0 L

B = 0.50 atm

C

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = C × 5.0 L

C = 0.60 atm

D

P₁ × V₁ = P₂ × V₂

1.5 atm × 2.0 L = 0.75 atm × D

D = 4.0 L

4 0
3 years ago
Read 2 more answers
(will give brainliest!)
Flura [38]

Answer:

D) cot(C) = 1/2.

Step-by-step explanation:

We can go through each choice and examine is validity.

Choice A)

We have:

\displaystyle \sec B=\frac{3}{7}

Recall that secant is the ratio of the hypotenuse to the adjacent.

With respect to B, the adjacent is 6 and the hypotenuse is 7.

Therefore, sec(B) should be 7/6 instead.

A is incorrect.

Choice B)

We have:

\displaystyle \cot B=\frac{3}{2}

Cotangent is the ratio of the adjacent side to the opposite.

With respect to B, the adjacent side is 6 and the opposite side is 3.

Therefore, cot(B) = 6/3 = 2.

B is incorrect.

Choice C)

C is incorrect for the reasons listed in A.

Choice D)

We have:

\displaystyle \cot C=\frac{1}{2}

Again, cotangent is the ratio of the adjacent side to the opposite.

With respect to C, the adjacent side is 3 and the opposite side is 6.

So, cot(C) = 3/6 = 1/2.

Therefore, D is the correct choice!

8 0
3 years ago
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