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4 years ago

Help!!! Algebra 2 :( Due in 7Mins

Mathematics

1 answer:

LekaFEV [45]4 years ago

8 0

Answer

Step-by-step explanation: The chain rule states that the derivative of f(g(x)) is f'(g(x))⋅g'(x). In other words, it helps us differentiate *composite functions*.

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Can someone help me with #7 please ?

wolverine [178]

It is so easy !
The coin will land tails up is 132 times
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8 0

3 years ago

Read 2 more answers

Last Sunday 1.575 people visited the amusement park % of the visitors were adults , 16% were teenagers and 28 were children ages

jasenka [17]

Answer:

882 , 252 , 441

Step-by-step explanation:

There are some mistakes in question and the corrected one is written below:

Q. Last Sunday 1,575 people visited the amusement park. 56% of the visitors were adults, 16% were teenagers, and 28% were children ages 12 and under. Find the number of adults, teenagers, and children that visited the park.

Given:

Total number of people visited amusement park = 1,575

Percent of adult people = 56%

Percent of teenagers = 16%

Percent of children = 28%

Now, we have to find number of adults, teenagers, and children that visited the park last Sunday.

Solution:

Number of adults = $56\%\ of \ 1575=\frac{56}{100}\times1575= \frac{88200}{100} =882\ adults$

Number of teenagers = $16\%\ of\ 1575=\frac{16}{100} \times1575=\frac{25200}{100} =252\ teenagers$

Number of children = $28\%\ of\ 1575=\frac{28}{100} \times1575=\frac{44100}{100} =441\ children$

Therefore, the number of adults are 882 , teenagers are 252 , and children are 441 that visited the park last Sunday.

6 0

3 years ago

Please sombody actually help me im stuck on this.

Vikki [24]

Answer:

A=6

B=19

C=55

D=119

E=70

7 0

3 years ago

Read 2 more answers

I)x-1 by 4=3<br>ii)3x+6 by 2=3 by 2<br>iii)3x-1by5=2x+3by7

suter [353]

Answer:

13,-1,2

Step-by-step explanation:

i hope it is helpful......for you

3 0

3 years ago

Solve the system of equations algebraically: x^2 +y^2 =25, y=x^2 +3

aalyn [17]

Answer:

${ \tt{ {x}^{2} + {y}^{2} = 25 - - - \{eqn(a) \}}} \\ { \tt{y = {x}^{2} + 3 - - - \{eqn(b) \} }}$

» substitute y in eqn(a) with y in eqn(b)

${ \tt{ {x}^{2} + ( {x}^{2} + 3) {}^{2} = 25}} \\ { \tt{ {x}^{2} + ( {x}^{2} + 6x + 9) = 25}} \\ { \tt{2 {x}^{2} + 6x + 9 = 25 }} \\ { \tt{2 {x}^{2} + 6x - 16 = 0}} \\ { \tt{x = 1.7 \: \: and \: \: - 4.7}}$

» Find y in eqn(b)

${ \tt{y = {x}^{2} + 3 }} \\ { \tt{y = 5.89 \: \: and \: \: 25.09}}$

8 0

3 years ago