2b+h = 4.82
b+2h = 3.70
multiply the second equation by 2:
2b + 4h = 7.40
subtract the first equation from it:
3h = 2.58
h = 0.86
Answer:
Algebra
Topics
How do you find the intercepts of x2y−x2+4y=0?
Algebra Graphs of Linear Equations and Functions Intercepts by Substitution
2 Answers
Gió
Mar 24, 2015
For the intercepts you set alternately x=0 and y=0 in your function:
and graphically:
Answer link
Alan P.
Mar 24, 2015
On the X-axis y=0
So
x2y−x2+4y=0
becomes
x2(0)−x2+4(0)=0
→−x2=0
→x=0
On the Y-axis x=0
and the original equation
x2y−x2+4y=0
becomes
(0)2y−(0)2+4y=0
→y=0
The only intercept for the given equation occurs at (0,0)
Answer link
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Answer:
question 13 = D
Step-by-step explanation:
because you do some math, open a calculator and boom, you have that.
Answer:
The equation is not a function.
Step-by-step explanation:
We are given that
Function: It is mapping between the values of two sets A and B.
Each element of A has unique value in set B.
By definition of function
In given function
y has no unique value for each value of x.
Substitute x=0
Hence, it is not a function.
Answer:
291.666666667
Step-by-step explanation:
Rounds to 291.7
