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Karo-lina-s [1.5K]
3 years ago
15

Charlie picks 468 tomatoes from his garden. He puts 12 tomatoes in each bag. He sells each bag for $8. What TWO equations can Ch

arlie use to find the amount of money he will, earn, if he sells all of the bags, b? *
A 468 ➗ 8 = b
B 12 ➗ 468 = b
C 468 ➗ 12 = b
D b ➗ 8 = t
E 12 x b = t
F b x 8 = t
Mathematics
1 answer:
jeka57 [31]3 years ago
5 0

Answer:

Step-by-step explanation:

A

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A- 6=9. Please help
olchik [2.2K]

Answer:

a = 15

Step-by-step explanation:

6 + 9 = 15

a = 15

15 - 6 = 9

yes

3 0
3 years ago
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How much greater is the area of a a square with a side length of 8 inches than the area of a circle with radius of 4 inches?
expeople1 [14]
Area of a square= l²
                           = 8×8 = 64 in²

Area of  a circle= πr²
                         = π × 4²
                         = 50.3 in²
Difference = 64 - 50.3 = 13.7 in²
7 0
3 years ago
In the Pacific, Allied forces began to take Japanese territory by _[blank].
Tomtit [17]
Beach invasions beach invasions
5 0
3 years ago
You roll a pair of honest dice. If you roll a total of 7, you win $18; if you roll a total of 11, you win $54; if you roll any o
amm1812
Answer: -1
The negative value indicates a loss

============================================================

Explanation:

Define the three events
A = rolling a 7
B = rolling an 11
C = roll any other total (don't roll 7, don't roll 11)

There are 6 ways to roll a 7. They are
1+6 = 7
2+5 = 7
3+4 = 7
4+3 = 7
5+2 = 7
6+1 = 7
Use this to compute the probability of rolling a 7
P(A) = (number of ways to roll 7)/(number total rolls) = 6/36 = 1/6
Note: the 36 comes from 6*6 = 36 since there are 6 sides per die

There are only 2 ways to roll an 11. Those 2 ways are:
5+6 = 11
6+5 = 11
The probability for event B is P(B) = 2/36 = 1/18

Since there are 6 ways to roll a "7" and 2 ways to roll "11", there are 6+2 = 8 ways to roll either event. 
This leaves 36-8 = 28 ways to roll anything else
P(C) = 28/36 = 7/9

-----------------------------

In summary so far,
P(A) = 1/6
P(B) = 1/18
P(C) = 7/9

The winnings for each event, let's call it W(X), represents the prize amounts.
Any losses are negative values
W(A) = amount of winnings if event A happens 
W(B) = amount of winnings if event B happens
W(C) = amount of winnings if event C happens
W(A) = 18
W(B) = 54
W(C) = -9

Multiply the probability P(X) values with the corresponding W(X) values
P(A)*W(A) = (1/6)*(18) = 3
P(B)*W(B) = (1/18)*(54) = 3
P(C)*W(C) = (7/9)*(-9) = -7

Add up those results
3+3+(-7) = -1

The expected value for this game is -1.
The player is expected to lose on average 1 dollar per game played.


Note: because the expected value is not 0, this is not a fair game.


7 0
3 years ago
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EastWind [94]
U do 4/20 = p/100 then u cross multiply the 4 with 100 getting u 400, then divide the 400 by 20, giving u the answer of 20%
8 0
3 years ago
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