Answer:
The product of the other two zeros is c
Step-by-step explanation:
Let α, β and γ be the zeros of the polynomial x³ + ax² + bx + c. Since one of the zeros is -1, therefore let γ = -1. Hence:
sum of the roots = α + β + γ = -a
-1 + β + γ = -a
β + γ = -a + 1
αβ + αγ + βγ = b
-1(β) + (-1)γ + βγ = b
-β -γ + βγ = b
Also, the product of the zeros is equal to -c, hence:
αβγ = -c
-1(βγ) = -c
βγ = c
Hence the product of the other two zeros is c
The answer is 326. this is simple.
The point that corresponds to the real zero of the graph of y=log3(x+2)-1 is (1, 0)
<h3>Logarithm function</h3>
Given the logarithmic function expressed as:
y=log3(x+2)-1
The point that corresponds to the real zero of the graph is at the point where y = 0
log3(x+2)-1 = 0
log3(x+2) = 1
log3(x+2) = log3 3
x + 2 = 3
x = 3 - 2
x = 1
Hene the point that corresponds to the real zero of the graph of y=log3(x+2)-1 is (1, 0)
Learn more on logarithm function here: brainly.com/question/13473114
