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FrozenT [24]
3 years ago
5

“IF YOU ARE GIVEN 2 SEGMENT LENGTHS, DESCRIBE HOW YOU WOULD FIND THE RANGE OF POSSIBLE LENGTHS OF THE THIRD SIDE?” (BEST ONE GET

BRAINLIEST)

Mathematics
1 answer:
Ainat [17]3 years ago
3 0

Answer:

To find a range of values for the third side when given two lengths, write two inequalities: one inequality that assumes the larger value given is the longest side in the triangle and one inequality that assumes that the third side is the longest side in the triangle. Combine the two inequalities for the final answer.

Step-by-step explanation:

You might be interested in
State who is correct and explain why
Ivan

Answer:

12.4+3√7 is  irrational

Step-by-step explanation:

12.4 is a rational number

3√7 is an irrational number

<u>The sum of a rational number and an irrational number is irrational.</u>

So, 12.4+3√7 is  irrational

4 0
3 years ago
Help me plz ASAP<br> A.2<br> B.1/2<br> C.2/3<br> D.3/2
BARSIC [14]

A

Step-by-step explanation:

First and foremost, we can rule out B and C because they are less than one and would make the hexagon smaller instead of bigger. Now, when we measure the units, we see that it goes up by 2 squares on the graph. So, by process of elimination and measurement, we get the answer of A.

3 0
2 years ago
By copying and completing the working below, work out 3 + 1 16 Give your answer as a fraction in its simplest form.
Ksenya-84 [330]

Answer:

Assuming the question is:  3 + 1 16  [I see no "working below."

Step-by-step explanation:

3 + 1 16

48/16 + (16/16 + 1/16)  [Make all numbers into fractions using 16 as the denominator.  E.g. 48/16 = 3.

Add:  48/16 + (16/16 + 1/16)

  (48+16+1)/16

=63/16

[Also equal to 3 15/16]

7 0
2 years ago
How many different 10-letter words (real or imaginary) can be formed from the letters of the word LITERATURE?
nordsb [41]

Answer:

The number of words that can be formed from the word "LITERATURE" is 453600

Step-by-step explanation:

Given

Word: LITERATURE

Required: Number of 10 letter word that can be formed

The number of letters in the word "LITERATURE" is 10

But some letters are repeated; These letters are T, E and R.

Each of the letters are repeated twice (2 times)

i.e.

Number of T = 2

Number of E = 2

Number of R = 2

To calculate the number of words that can be formed, the total number of possible arrangements will be divided by arrangement of each repeated character. This is done as follows;

Number of words that can be formed = \frac{10!}{2!2!2!}

Number of words = \frac{10 * 9 * 8 * 7 * 6 * 5 * 4 * 3 * 2 * 1}{2 * 1 * 2 * 1 * 2 * 1}

Number of words = \frac{3628800}{8}

Number of words = 453600

Hence, the number of words that can be formed from the word "LITERATURE" is 453600

8 0
3 years ago
Write the equation of a parabola whose focus is at (-7, 3) and whose directrix is the line x = -3.
Sav [38]

Check the picture below.

now, let's keep in mind that, the vertex is half-way between the focus point and the directrix, it's a "p" distance from each other.

since this horizontal parabola is opening to the left-hand-side, "p" is negative, notice in the picture, "p" is 2 units, and since it's negative, p = -2.

its vertex is half-way between those two guys, so that puts the vertex at (-5, 3)

\bf \textit{parabola vertex form with focus point distance} \\\\ \begin{array}{llll} 4p(x- h)=(y- k)^2 \\\\ 4p(y- k)=(x- h)^2 \end{array} \qquad \begin{array}{llll} vertex\ ( h, k)\\\\ p=\textit{distance from vertex to }\\ \qquad \textit{ focus or directrix} \end{array} \\\\[-0.35em] \rule{34em}{0.25pt}\\\\ \begin{cases} h=-5\\ k=7\\ p=-2 \end{cases}\implies 4(-2)[x-(-5)]=[y-7]^2 \\\\\\ -8(x+5)=(y-7)^2\implies x+5=\cfrac{(y-7)^2}{-8}\implies \boxed{x=-\cfrac{1}{8}(y-7)^2-5}

7 0
3 years ago
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