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hodyreva [135]
3 years ago
12

Solve the equation for x, where x is a real number (5 points): 2x^2 + 8x + 3 = 0

Mathematics
1 answer:
Aleonysh [2.5K]3 years ago
6 0
To find the solutions to this equation, we can apply the quadratic formula. This quadratic formula solves equations of the form ax^2 + bx + c = 0
                                           x = [ -b ± √(b^2 - 4ac) ] / (2a)
                                           x = [ -8 ± √((8)^2 - 4(2)(3)) ] / ( 2(2) )
                                           x = [-8 ± √(64 - (24) ) ] / ( 4 )
                                           x = [-8 ± √(40) ] / ( 4)
                                           x = [-8 ± 2*sqrt(10) ] / ( 4 )
                                           x = -2 ± sqrt(10)/2
The answers are -2 + sqrt(10)/2 and -2 - sqrt(10)/2.
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Answer:

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Step-by-step explanation:

1. Expand.

6x − 18 + 10 = 8x − 10

2. Simplify 6x − 18 + 10 to 6x − 8.

6x − 8 = 8x − 10

3. Subtract 6x from both sides.

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5. Add 10 to both sides.

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6. Simplify −8 + 10 to 2.

2 = 2x

7. Divide both sides by 2.

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When Joanne checked her work by substituting the value of the variable back into the equation, she got an answer of 12.34 = 12.3
Arada [10]
See could have got the correct answer because if there was more numbers in the decimal you can round it to get .34 or because both answers have 12.3 and it doesnt matter about the other numbers after 3
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Read 2 more answers
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