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mr_godi [17]
2 years ago
5

Distance between -6, -4, and -9, 0 on a coordinate plane

Mathematics
1 answer:
dangina [55]2 years ago
3 0

Answer:

hdjixuwowiuejeutst81+€+"77#8"72782+"6€(3;+€#+:"8+#-7_61+*9*#7€9"+€9€71923791-499€9782833927258160094720&72700828292792(#+€928€+9#+#827€-92727€!#}¥

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Please help me I will give a brainly!!!!
nydimaria [60]

Answer:

Yes

Step-by-step explanation:

1 : The athlete's hands push the medicine ball forward. The medicine ball pushes the athlete's hands backward.

2: Friction

3: The first pair of action-reaction force pairs is: foot A pushes ball B to the right; and ball B pushes foot A to the left. The second pair of action-reaction force pairs is: foot C pushes ball B to the left; and ball B pushes foot C to the right

7 0
2 years ago
On the 25th of every month, Tamesha pays her rent
Alchen [17]
Ok? What’s the question?
3 0
2 years ago
Angle a is one ninth as large as its complement angle b
Arte-miy333 [17]
Angle a is one ninth as large as its complement angle b
a+b=180
a=9b
a=18
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iş right answer plese let me know
8 0
3 years ago
last week rafael drove m miles. this week he drove 153 miles. using m, write an expression for the total number of miles he drov
zzz [600]

The expression for the total number of miles he drove in the two weeks is m + 153

<h3>How to determine the expression for the total number of miles he drove in the two weeks?</h3>

The given parameters are

Last week = m miles

This week = 153 miles

The expression for the total number of miles he drove in the two weeks is

Expression = Last week + This week

This gives

Expression = m + 153

Hence, the expression for the total number of miles he drove in the two weeks is m + 153

Read more about expressions at

brainly.com/question/723406

#SPJ1

5 0
1 year ago
Divide.<br> a.1 − 2i/2i<br> b. 5 − 2i/5 + 2i<br> c.√3 − 2i/−2 − √3i
Umnica [9.8K]

Answer:

(a) \frac{-1i}{2}-1[/tex]

(b) \frac{20i+21}{29}

(c) i

Step-by-step explanation:

We have to perform division

(a) \frac{1-2i}{2i}

So after division

\frac{1-2i}{2i}=\frac{1}{2i}-\frac{2i}{2i}=\frac{-1i}{2}-1

(b) We have given expression \frac{5-2i}{5+2i}

After rationalizing \frac{5-2i}{5+2i}\times \frac{5-2i}{5-2i}=\frac{(5-2i)^2}{25+4}=\frac{25+4i^2+20i}{29}=\frac{20i+21}{29}

(c) We have given expression \frac{\sqrt{3}-2i}{-2-\sqrt{3i}}

After rationalizing

\frac{\sqrt{3}-2i}{-2-\sqrt{3i}}\times \frac{-2+\sqrt{3i}}{-2+\sqrt{3i}}=\frac{-2\sqrt{3}+7i+2\sqrt{3}}{7}=\frac{7i}{7}=i

5 0
3 years ago
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