43 and 44, but it's closer to 43
Answer:
Step-by-step explanation:
a. The vertex is (1, -9). False. The vertex is (-1, -9).
b. The graph opens upward. True. That coefficient '6' is positive.
c. The graph is obtained by shifting the graph of f(x) = 6(x + 1)2 up 9 units. False. It's DOWN 9 units.
d. The graph is steeper than the graph of f(x) = x^2. True. The given function increases 6 times faster than does x^2.
e. The graph is the same as the graph of f(x) = 6x2 + 12x - 3.
Let's put f(x) = 6(x + 1)^2 -9 into standard form. Expanding the first term, we get f(x) = 6(x^2 + 2x + 1) - 9, or f(x) = 6x^2 + 12x + 6 - 9. YES, TRUE
<em><u>Answer:</u></em>
4 or 7 (Check the explanation to see which one your equation <em>actually</em> is.
<em><u>Step-by-step explanation:</u></em>
One thing I want to clarify for you, It's Evaluate, not Avaluate.
Okay so, we want to find the value of 2^3x-1 and we know x = 1.
You didn't really clarify if the expression was 
or 
, so I'll be doing both:
For , we should plug in x to get 
and then simplify to get 
.
2 to the power of 2 or is equal to 2 * 2 or 4.
The second one, , we should plug in x to get 
and then to become 
. 2 to the power of 3 or 
is 8 and then minus 1 is 7.
(4(2)=8*8*8=512÷6=85.333333
(4-2)=2
8-2=6
8*2=16
8÷2=4
8+2=10
whichever operation it is
