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Lena [83]
3 years ago
11

Solve the inequality 2(x-3)-5x<9

Mathematics
2 answers:
kvasek [131]3 years ago
6 0

Answer:

Step-by-step explanation:

2(x-3)-5x<9 expand left side

2x-6-5x<9. group like terms on left side

-3x-6<9. add 6 to each side

-3x<15. divide each side by -3 (reverse sign because of division by a negative)

x>-5

gayaneshka [121]3 years ago
5 0

Answer:

x > -5

Step-by-step explanation:

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Does the point (2,3) satisfy the inequality 4x+3y&gt; 20
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No, (2 , 3) does not satisfy the inequality 4x + 3y > 20.

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~

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A farmer has 18 animals (cows and chickens). He counts 60 legs. How many chickens does he have?
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Chickens have 2 legs and cows have 4
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This trapezium is drawn on a centimetre grid.<br> Find the area of the trapezium.
aivan3 [116]

Answer:

20 unit²

Step-by-step explanation:

A trapezium is given to us on the grid and we need to find out the area of the trapezium . In order to find the area , we need to find the measure of the parallel sides and the distance between the parallel sides.

<u>From </u><u>the</u><u> </u><u>grid</u><u> </u><u>:</u><u>-</u>

\rm\implies Side_1 = 7 \ units

\rm\implies Side_2 = 3 \ units

\rm\implies \perp \ Distance =4  \ units

Now here we got the two parallel sides of the trapezium and the distance between the two parallel sides. Now we can find the area as ,

\rm\implies Area_{Trapezium}= \dfrac{1}{2}\times ( s_1 + s_2) \times   \perp \ Distance \\\\\rm\implies Area = \dfrac{1}{2} \times ( 7 + 3 ) \times 4 \ unit^2 \\\\\rm\implies Area = \dfrac{1}{2} \times ( 10) \times 4 \ unit^2 \\\\\rm\implies\boxed{\rm  Area = 20 \ unit^2}

3 0
3 years ago
Please answer the following
natulia [17]

Answer:

cot∅ = (-2√30)/7.

Step-by-step explanation:

Given the value of csc∅ = -13/7 and ∅ is in quad III.

We know y = r sin∅ and r > 0. So csc∅ = r/y = -13/7 = 13/(-7).

It means y = -7, r = 13.

We know x² + y² = r².

x² = r² - y²

x² = (13)² - (-7)² = 169 - 49 = 120.

x = √120 = 2√30.

we know cot∅ = x/y = (2√30)/(-7) = (-2√30)/7.

Hence, cot∅ = (-2√30)/7.

4 0
4 years ago
Flagpole to the ground using a piece of rope that is 10 feet long. He is going to tie the rope to the top of the flagpole and th
Flauer [41]

Answer:

<h3>6 feet</h3>

Step-by-step explanation

Using the pythagoras theorem;

Given

The length of the flag pole = 8 feet = opposite side

Length of the rope = 10 feet = hypotenuse

To determine how far out on the ground he need to secure the rope from the flagpole so that the rope is tight, we need to look for the adjacent. Using the equation

hyp² = opp² + adj²

10² = 8² + adj²

adj² = 100-64

adj² = 36

adj = √36

adj = 6feet

Hence the rope should be placed 6feet out of the ground

4 0
3 years ago
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