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Jet001 [13]
3 years ago
8

Describe a sequence of three transformations of ABC that will produce the image A’ B’ C’.

Mathematics
2 answers:
rusak2 [61]3 years ago
8 0

Answer:

steps below

Step-by-step explanation:

A(-1,-1)   B(-2,-3)  C(-3,-1)

1. Reflection over y=-1    A(-1,-1)   B(-2,1)  C(-3,-1)

2. Shift to right 4 units   A(3,-1)   B(2,1)  C(1,-1)

3. Dilation with factor 2 and center C'(1.-1)      A'(5,-1)   B'(3,3)  C'(1,-1)

Leokris [45]3 years ago
6 0

Answer:

Reflect over x-axis, Translate 5 units right, Dilate by a factor of 2

Step-by-step explanation:

I think this is correct The dilation probably isn't but those are the three transformations. But i am pretty sure i am right.

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The frequency of D3 is 146.83 Hz. What is the frequency of D5, which is two octaves above D3?
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Answer: D

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Step-by-step explanation:

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3 years ago
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5 0
3 years ago
Tasha believes that she can rewrite the difference of 120 minus 36 as a product of the GCF of the two numbers and the difference
xz_007 [3.2K]

Answer:

GCF = 12

For the values 36, 120:

Solution by Factorization:

The factors of 36 are: 1, 2, 3, 4, 6, 9, 12, 18, 36

The factors of 120 are: 1, 2, 3, 4, 5, 6, 8, 10, 12, 15, 20, 24, 30, 40, 60, 120

Then the greatest common factor is 12.



Pair Share:

The GCF of 120 and 36 is ======> 12

so, 120 – 36 can be written as:

12 × 10 – 12 × 3, which is 12 × (10 – 3) or 12 × 7.


Answer: ========> Therefore, Tasha is correct






Hope that helps!!!! : )




4 0
3 years ago
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