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bogdanovich [222]
3 years ago
13

Please help me figure out what kind of triangle this is!!!

Mathematics
1 answer:
daser333 [38]3 years ago
4 0
It would be there is not enough information because you need the angles to find out what what degrees it has in it. Hope this helps :)
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Dylan wants to determine a 90 percent confidence interval for the true proportion of high school students in the area who attend
Over [174]

Answer:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.64})^2}=747.11  

And rounded up we have that n=748

Step-by-step explanation:

In order to find the critical value we need to take in count that we are finding the interval for a proportion, so on this case we need to use the z distribution. Since our interval is at 90% of confidence, our significance level would be given by \alpha=1-0.90=0.1 and \alpha/2 =0.05. And the critical value would be given by:

z_{\alpha/2}=-1.64, z_{1-\alpha/2}=1.64

The margin of error for the proportion interval is given by this formula:  

ME=z_{\alpha/2}\sqrt{\frac{\hat p (1-\hat p)}{n}}    (a)  

And on this case we have that ME =\pm 0.03 and we are interested in order to find the value of n, if we solve n from equation (a) we got:  

n=\frac{\hat p (1-\hat p)}{(\frac{ME}{z})^2}   (b)  

The best estimatr for the proportionis 0.5 since we don't have any other info provided. And replacing into equation (b) the values from part a we got:

n=\frac{0.5(1-0.5)}{(\frac{0.03}{1.64})^2}=747.11  

And rounded up we have that n=748

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Answer:

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Step-by-step explanation:

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Answer:

Step-by-step explanation:

m = -1/3 = Δy/Δx = (2 - 4) / (x - (-1)) = -2/(x + 1)

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