Not necessarily.

and

may be linearly dependent, so that their span forms a subspace of

that does not contain every vector in

.
For example, we could have

and

. Any vector

of the form

, where

, is impossible to obtain as a linear combination of these

and

, since

unless

and

.
6 sets of birds were in a brown crate and 2 sets of birds were in a green crate? How many birds altogether were in those crates.
Answer:
D, (1,2)
Step-by-step explanation:
It all comes down to substitution. In this case the coefficient of x is 3 and the coefficient of y is 4. The format of these coordinates being (x,y).
1. Plug in your x value (1 in this circumstance) and solve:
3(1) + 4y < 12
3 + 4y < 12
2. Plug in your y value (2 in this circumstance) and solve:
3 + 4(2) < 12
3 + 8 < 12
3. Solve
3 + 8 = 11
11 < 12
Answer:
a>−6
Step-by-step explanation:
−4(1−5a)>−124
Step 1: Simplify both sides of the inequality.
20a−4>−124
Step 2: Add 4 to both sides.
20a−4+4>−124+4
20a>−120
Step 3: Divide both sides by 20.
20a/20> −120/20
a>−6