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Fofino [41]
3 years ago
13

You roll a 6 sided die. What is P(roll great her than 4)? If necessary round your answer to 2 decimal place

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

1/3 = 0.33

Step-by-step explanation:

in a 6 sided die, there are numbers 1, 2, 3, 4, 5 and 6. So if you roll it once, there are 6 possible outcomes. so 6 is your sample space.

Out of all the possible outcomes, 5 and 6 are the only outcomes greater than 4.

P(an event occurring) = (number of ways it can occur)/(sample space)

∴p(roll greater than 4) = 2/6

                                     =1/3

                                     =0.333333333333333333333333............................

                                     =0.33 (when rounded off to the 2nd decimal place)

So that's it!!! Hope i helped ya :)

                                       

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12 is 75% of what number?
wolverine [178]
For this question you should say:
75/100 = 12/? 
so the ? is your answer:
12*100/75 = 16 :)))
I hope this is helpful
have a nice day
8 0
3 years ago
Can someone help me with solving systems by graphing please? (:​
Ket [755]

Answer:

Step-by-step explanation: In graphing there are two letters x, and y also called X-axis and Y-axis. They are called ordered pairs. To graph on the bottom of the graph are numbers 1-10 or more, those are X. At the left is a straight line numbers 1-10 or more. Now to actually graph if you get an ordered pair lets say, 3,4. the number on the left is the X, and the number on the right is the Y. There is an end in the X-axis, and Y-axis. Start from there, you will always start at the bottom then the left. Start at the 0,0 go three times to left at the bottom, then at the left go up four times. when you get 3,4 add a dot. Then that's your answer. It pretty easy. Hope it helps you!

8 0
4 years ago
The probability that a professor arrives on time is 0.8 and the probability that a student arrives on time is 0.6. Assuming thes
saul85 [17]

Answer:

a)0.08  , b)0.4  , C) i)0.84  , ii)0.56

Step-by-step explanation:

Given data

P(A) =  professor arrives on time

P(A) = 0.8

P(B) =  Student aarive on time

P(B) = 0.6

According to the question A & B are Independent  

P(A∩B) = P(A) . P(B)

Therefore  

{A}' & {B}' is also independent

{A}' = 1-0.8 = 0.2

{B}' = 1-0.6 = 0.4

part a)

Probability of both student and the professor are late

P(A'∩B') = P(A') . P(B')  (only for independent cases)

= 0.2 x 0.4

= 0.08

Part b)

The probability that the student is late given that the professor is on time

P(\frac{B'}{A}) = \frac{P(B'\cap A)}{P(A)} = \frac{0.4\times 0.8}{0.8} = 0.4

Part c)

Assume the events are not independent

Given Data

P(\frac{{A}'}{{B}'}) = 0.4

=\frac{P({A}'\cap {B}')}{P({B}')} = 0.4

P({A}'\cap {B}') = 0.4 x P({B}')

= 0.4 x 0.4 = 0.16

P({A}'\cap {B}') = 0.16

i)

The probability that at least one of them is on time

P(A\cup B) = 1- P({A}'\cap {B}')  

=  1 - 0.16 = 0.84

ii)The probability that they are both on time

P(A\cap  B) = 1 - P({A}'\cup {B}') = 1 - [P({A}')+P({B}') - P({A}'\cap {B}')]

= 1 - [0.2+0.4-0.16] = 1-0.44 = 0.56

6 0
3 years ago
Helppppppppppppppppp asappppppp
Pani-rosa [81]

Answer:

140

Step-by-step explanation:

<u>As per picture:</u>

∠PTQ  and ∠RTS are vertical angles and they are equal

  • ∠PTQ = (x + 28)°
  • ∠RTS = (2x + 16)°
  • ∠PTQ  = ∠RTS
  • x + 28 = 2x + 16
  • 2x - x = 28 - 16
  • x = 12

∠PTR is supplementary with ∠PTQ  and their sum is 180°

  • ∠PTQ = 12 + 28 = 40°
  • ∠PTR = 180 - 40 = 140°

6 0
4 years ago
225 divided by t-4=6.4
frosja888 [35]

Answer: t=1125/52=21.635

Step-by-step explanation:

5 0
1 year ago
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