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Fofino [41]
3 years ago
13

You roll a 6 sided die. What is P(roll great her than 4)? If necessary round your answer to 2 decimal place

Mathematics
1 answer:
brilliants [131]3 years ago
4 0

Answer:

1/3 = 0.33

Step-by-step explanation:

in a 6 sided die, there are numbers 1, 2, 3, 4, 5 and 6. So if you roll it once, there are 6 possible outcomes. so 6 is your sample space.

Out of all the possible outcomes, 5 and 6 are the only outcomes greater than 4.

P(an event occurring) = (number of ways it can occur)/(sample space)

∴p(roll greater than 4) = 2/6

                                     =1/3

                                     =0.333333333333333333333333............................

                                     =0.33 (when rounded off to the 2nd decimal place)

So that's it!!! Hope i helped ya :)

                                       

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Express the following repeating decimal as a fraction in simplest form.
Ivenika [448]

Answer:

0.\overline{369} = \frac{41}{111}

Step-by-step explanation:

x = 0.369369369...

10x = 3.69369369...

100x = 36.9369369...

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1000x - x = 369

999x = 369

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4 0
3 years ago
A machine has four components, A, B, C, and D, set up in such a manner that all four parts must work for the machine to work pro
olchik [2.2K]

Answer:

0.756

Step-by-step explanation:

It is given that a machine has four components, A, B, C, and D.

P(A)=P(B)=0.93, P(C)=0.95,P(D)=0.92

If these components set up in such a manner that all four parts must work for the machine to work properly.

We need to find the probability that the machine works properly. It means we have to find the value of P(A\cap B\cap C\cap D).

If two events X and Y are independent, then

P(X\cap Y)=P(X)\times P(Y)

Assume the probability of one part working does not depend on the functionality of any of the other parts.

P(A\cap B\cap C\cap D)=P(A)\times P(B)\times P(C)\times P(D)

Substitute the given values.

P(A\cap B\cap C\cap D)=0.93\times 0.93\times 0.95\times 0.92

P(A\cap B\cap C\cap D)=0.7559226

P(A\cap B\cap C\cap D)\approx 0.756

Therefore, the probability that the machine works properly is 0.756.

7 0
3 years ago
The number of oranges a grocery store bought this year was 15% more than the number of oranges bought last year. This year the s
snow_tiger [21]

Answer:

The original number of oranges purchased is 260

Step-by-step explanation:

Let the original number of oranges purchased be x

We are given that The number of oranges a grocery store bought this year was 15% more than the number of oranges bought last year.

So, Oranges bought this year = x+15\%x=x+\frac{15}{100}x=1.15x

We are given that This year the store bought 299 oranges.

So, 1.15 x= 299

x=\frac{299}{1.15}

x=260

Hence the original number of oranges purchased is 260

4 0
3 years ago
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