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2 years ago

Can someone please help, ty!! (Will mark brainliest)

Mathematics

2 answers:

Oliga [24]2 years ago

7 0

Answer:

Arcadia

Step-by-step explanation:

the line in the box is the median and Arcadia is bigger than Millersburg

Sergeeva-Olga [200]2 years ago

3 0

Answer:

millersburg

Step-by-step explanation:

hope this helps srry if it doesn't

plz mark me brainlist

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Simplify the expression. (2.9)2 =

guapka [62]

Answer:

5.8

Step-by-step explanation:

2.9*2=5.8 give brainliest pls

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2 years ago

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HELP ME!! I WILL GIVE BRAINLIEST!!! Express your answer in SCIENTIFIC NOTATION. 9.3 × 10⁷ - 3.4 × 10⁶ = __________ plz help!!

DanielleElmas [232]

Answer:

9.3 × 10⁷ - 3.4 × 10⁶ = 89 600 000

Which is 8.96*10^7 in scientific notation

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3 years ago

If f(x)=3x-2 and g(x)=x^2+1, find f(g(-1)) and g(f(3))

julsineya [31]

Answer:

$f(g(-1))=4$

$g(f(3))=50$

Step-by-step explanation:

We know the definition of both functions: $f(x)=3x-2$ , and $g(x)=x^2+1$

A) In order to evaluate what $f(g(-1)) is$ , let's first investigate what g(-1) is using the definition for this function:

$g(x)=x^2+1\\g(-1)=(-1)^2+1\\g(-1)=1+1\\g(-1)=2$

Now let's find what f(2) is using f(x) definition: $f(x)=3x-2\\f(2)=3(2)-2\\f(2)=6-2\\f(2)=4$

B) In order to evaluate what $g(f(3)) is$ , let's first investigate what f(3) is using the definition for this function:

$f(x)=3x-2\\f(3)=3(3)-2\\f(3)=9-2\\f(3)=7$

Now let's find what g(7) is using the definition for this function:

$g(x)=x^2+1\\g(7)=(7)^2+1\\g(7)=49+1\\g(7)=50$

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2 years ago

Use a special right triangle to write tan 60° in simplest radical form.

Tems11 [23]

Tan 60 in radical for is square root of 3

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2 years ago

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Imagine that you need to compute e^0.4 but you have no calculator or other aid to enable you to compute it exactly, only paper a

labwork [276]

Answer:

0.0032

Step-by-step explanation:

We need to compute $e^{0.4}$ by the help of third-degree Taylor polynomial that is expanded around at x = 0.

Given :

$e^{0.4}$ < e < 3

Therefore, the Taylor's Error Bound formula is given by :

$|\text{Error}| \leq \frac{M}{(N+1)!} |x-a|^{N+1}$ , where $M=|F^{N+1}(x)|$

$\leq \frac{3}{(3+1)!} |-0.4|^4$

$\leq \frac{3}{24} \times (0.4)^4$

$\leq 0.0032$

Therefore, |Error| ≤ 0.0032

4 0

2 years ago